DateTime.DaysInMonth(Int32, Int32) Méthode
Définition
Important
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Retourne le nombre de jours compris dans le mois et l'année spécifiés.
public:
static int DaysInMonth(int year, int month);public static int DaysInMonth (int year, int month);static member DaysInMonth : int * int -> intPublic Shared Function DaysInMonth (year As Integer, month As Integer) As IntegerParamètres
- year
- Int32
Année.
- month
- Int32
Mois (chiffre compris entre 1 et 12).
Retours
Nombre de jours de month pour le year spécifié.
Par exemple, si month est égal à 2 pour février, la valeur de retour est 28 ou 29, suivant que year est une année bissextile ou non.
Exceptions
month est inférieur à 1 ou supérieur à 12.
- ou -
year est inférieur à 1 ou supérieur à 9 999.
Exemples
L’exemple suivant montre comment utiliser la DaysInMonth méthode pour déterminer le nombre de jours en juillet 2001, 1998 février (une année non bissextile) et 1996 février (année bissextile).
using namespace System;
int main()
{
const int July = 7;
const int Feb = 2;
int daysInJuly = System::DateTime::DaysInMonth( 2001, July );
Console::WriteLine(daysInJuly);
// daysInFeb gets 28 because the year 1998 was not a leap year.
int daysInFeb = System::DateTime::DaysInMonth( 1998, Feb );
Console::WriteLine(daysInFeb);
// daysInFebLeap gets 29 because the year 1996 was a leap year.
int daysInFebLeap = System::DateTime::DaysInMonth( 1996, Feb );
Console::WriteLine(daysInFebLeap);
}
// The example displays the following output:
// 31
// 28
// 29
using System;
class Example
{
static void Main()
{
const int July = 7;
const int Feb = 2;
int daysInJuly = System.DateTime.DaysInMonth(2001, July);
Console.WriteLine(daysInJuly);
// daysInFeb gets 28 because the year 1998 was not a leap year.
int daysInFeb = System.DateTime.DaysInMonth(1998, Feb);
Console.WriteLine(daysInFeb);
// daysInFebLeap gets 29 because the year 1996 was a leap year.
int daysInFebLeap = System.DateTime.DaysInMonth(1996, Feb);
Console.WriteLine(daysInFebLeap);
}
}
// The example displays the following output:
// 31
// 28
// 29
Class Example
Public Shared Sub Main()
Const July As Integer = 7
Const Feb As Integer = 2
Dim daysInJuly As Integer = System.DateTime.DaysInMonth(2001, July)
Console.WriteLine(daysInJuly)
' daysInFeb gets 28 because the year 1998 was not a leap year.
Dim daysInFeb As Integer = System.DateTime.DaysInMonth(1998, Feb)
Console.WriteLine(daysInFeb)
' daysInFebLeap gets 29 because the year 1996 was a leap year.
Dim daysInFebLeap As Integer = System.DateTime.DaysInMonth(1996, Feb)
Console.WriteLine(daysInFebLeap)
End Sub
End Class
' The example displays the following output:
' 31
' 28
' 29
L’exemple suivant affiche le nombre de jours de chaque mois d’une année spécifiée dans un tableau d’entiers.
using System;
using System.Globalization;
public class Example
{
public static void Main()
{
int[] years = { 2012, 2014 };
DateTimeFormatInfo dtfi = DateTimeFormatInfo.CurrentInfo;
Console.WriteLine("Days in the Month for the {0} culture " +
"using the {1} calendar\n",
CultureInfo.CurrentCulture.Name,
dtfi.Calendar.GetType().Name.Replace("Calendar", ""));
Console.WriteLine("{0,-10}{1,-15}{2,4}\n", "Year", "Month", "Days");
foreach (var year in years) {
for (int ctr = 0; ctr <= dtfi.MonthNames.Length - 1; ctr++) {
if (String.IsNullOrEmpty(dtfi.MonthNames[ctr]))
continue;
Console.WriteLine("{0,-10}{1,-15}{2,4}", year,
dtfi.MonthNames[ctr],
DateTime.DaysInMonth(year, ctr + 1));
}
Console.WriteLine();
}
}
}
// The example displays the following output:
// Days in the Month for the en-US culture using the Gregorian calendar
//
// Year Month Days
//
// 2012 January 31
// 2012 February 29
// 2012 March 31
// 2012 April 30
// 2012 May 31
// 2012 June 30
// 2012 July 31
// 2012 August 31
// 2012 September 30
// 2012 October 31
// 2012 November 30
// 2012 December 31
//
// 2014 January 31
// 2014 February 28
// 2014 March 31
// 2014 April 30
// 2014 May 31
// 2014 June 30
// 2014 July 31
// 2014 August 31
// 2014 September 30
// 2014 October 31
// 2014 November 30
// 2014 December 31
Imports System.Globalization
Module Example
Public Sub Main()
Dim years() As Integer = { 2012, 2014 }
Dim dtfi As DateTimeFormatInfo = DateTimeFormatInfo.CurrentInfo
Console.WriteLine("Days in the Month for the {0} culture " +
"using the {1} calendar",
CultureInfo.CurrentCulture.Name,
dtfi.Calendar.GetType.Name.Replace("Calendar", ""))
Console.WriteLine()
Console.WriteLine("{0,-10}{1,-15}{2,4}", "Year", "Month", "Days")
Console.WriteLine()
For Each [year] As Integer In years
For ctr As Integer = 0 To dtfi.MonthNames.Length - 1
If String.IsNullOrEmpty(dtfi.MonthNames(ctr)) Then
Continue For
End If
Console.WriteLine("{0,-10}{1,-15}{2,4}", [year],
dtfi.MonthNames(ctr),
DateTime.DaysInMonth([year], ctr + 1))
Next
Console.WriteLine()
Next
End Sub
End Module
' The example displays the following output:
' Days in the Month for the en-US culture using the Gregorian calendar
'
' Year Month Days
'
' 2012 January 31
' 2012 February 29
' 2012 March 31
' 2012 April 30
' 2012 May 31
' 2012 June 30
' 2012 July 31
' 2012 August 31
' 2012 September 30
' 2012 October 31
' 2012 November 30
' 2012 December 31
'
' 2014 January 31
' 2014 February 28
' 2014 March 31
' 2014 April 30
' 2014 May 31
' 2014 June 30
' 2014 July 31
' 2014 August 31
' 2014 September 30
' 2014 October 31
' 2014 November 30
' 2014 December 31
Remarques
La DaysInMonth méthode interprète toujours month et year comme le mois et l’année du calendrier grégorien, même si le calendrier grégorien n’est pas le calendrier actuel de la culture actuelle. Pour obtenir le nombre de jours dans un mois spécifié d’un calendrier particulier, appelez la méthode de ce calendrier GetDaysInMonth .