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ProcessModule.FileName Propriété

Définition

Obtient le chemin d'accès complet du module.

public:
 property System::String ^ FileName { System::String ^ get(); };
public string? FileName { get; }
public string FileName { get; }
member this.FileName : string
Public ReadOnly Property FileName As String

Valeur de propriété

Chemin d'accès qualifié complet qui définit l'emplacement du module.

Exemples

L'exemple de code suivant crée un processus pour l'application Notepad.exe. Le code itère au sein de la classe ProcessModuleCollection afin d’obtenir un objet ProcessModule pour chaque module de la collection. Les propriétés ModuleName et FileName sont utilisées pour afficher le nom du module et les informations du chemin complet pour chaque module.

Process^ myProcess = gcnew Process;

// Get the process start information of notepad.
ProcessStartInfo^ myProcessStartInfo = gcnew ProcessStartInfo( "notepad.exe" );

// Assign 'StartInfo' of notepad to 'StartInfo' of 'myProcess' object.
myProcess->StartInfo = myProcessStartInfo;

// Create a notepad.
myProcess->Start();
System::Threading::Thread::Sleep( 1000 );
ProcessModule^ myProcessModule;

// Get all the modules associated with 'myProcess'.
ProcessModuleCollection^ myProcessModuleCollection = myProcess->Modules;
Console::WriteLine( "File names of the modules associated with 'notepad' are:" );

// Display the 'FileName' of each of the modules.
for ( int i = 0; i < myProcessModuleCollection->Count; i++ )
{
   myProcessModule = myProcessModuleCollection[ i ];
   Console::WriteLine( "{0:s} : {1:s}", myProcessModule->ModuleName,  myProcessModule->FileName );
}
myProcessModule = myProcess->MainModule;

// Display the 'FileName' of the main module.
Console::WriteLine( "The process's main module's FileName is: {0}", myProcessModule->FileName );
myProcess->CloseMainWindow();
using (Process myProcess = new Process())
{
    // Get the process start information of notepad.
    ProcessStartInfo myProcessStartInfo = new ProcessStartInfo("notepad.exe");
    // Assign 'StartInfo' of notepad to 'StartInfo' of 'myProcess' object.
    myProcess.StartInfo = myProcessStartInfo;
    // Create a notepad.
    myProcess.Start();
    System.Threading.Thread.Sleep(1000);
    ProcessModule myProcessModule;
    // Get all the modules associated with 'myProcess'.
    ProcessModuleCollection myProcessModuleCollection = myProcess.Modules;
    Console.WriteLine("File names of the modules associated "
        + "with 'notepad' are:");
    // Display the 'FileName' of each of the modules.
    for (int i = 0; i < myProcessModuleCollection.Count; i++)
    {
        myProcessModule = myProcessModuleCollection[i];
        Console.WriteLine(myProcessModule.ModuleName + " : "
            + myProcessModule.FileName);
    }
    // Get the main module associated with 'myProcess'.
    myProcessModule = myProcess.MainModule;
    // Display the 'FileName' of the main module.
    Console.WriteLine("The process's main module's FileName is: "
        + myProcessModule.FileName);
    myProcess.CloseMainWindow();
}
Using myProcess As New Process()
    ' Get the process start information of notepad.
    Dim myProcessStartInfo As New ProcessStartInfo("notepad.exe")
    ' Assign 'StartInfo' of notepad to 'StartInfo' of 'myProcess' object.
    myProcess.StartInfo = myProcessStartInfo
    ' Create a notepad.
    myProcess.Start()
    System.Threading.Thread.Sleep(1000)
    Dim myProcessModule As ProcessModule
    ' Get all the modules associated with 'myProcess'.
    Dim myProcessModuleCollection As ProcessModuleCollection = myProcess.Modules
    Console.WriteLine("File names of the modules associated " +
                            "with 'notepad' are:")
    ' Display the 'FileName' of each of the modules.
    Dim i As Integer
    For i = 0 To myProcessModuleCollection.Count - 1
        myProcessModule = myProcessModuleCollection(i)
        Console.WriteLine(myProcessModule.ModuleName + " : " + myProcessModule.FileName)
    Next i
    ' Get the main module associated with 'myProcess'.
    myProcessModule = myProcess.MainModule
    ' Display the 'FileName' of the main module.
    Console.WriteLine("The process's main module's FileName is: " + myProcessModule.FileName)
    myProcess.CloseMainWindow()
End Using

Remarques

Si le nom de fichier est plus long que le nombre maximum de caractères autorisé, le nom de fichier est tronqué.

S’applique à