Tuple<T1,T2>.Item1 Propriété

Définition

Espace de noms:

System

Assembly:

System.Runtime.dll

Assembly:

mscorlib.dll

Assembly:

netstandard.dll

Obtient la valeur du premier composant de l'objet Tuple<T1,T2> actif.

public:
 property T1 Item1 { T1 get(); };

public T1 Item1 { get; }

member this.Item1 : 'T1

Public ReadOnly Property Item1 As T1

Valeur de propriété

T1

Valeur du premier composant de l'objet Tuple<T1,T2> actif.

Exemples

L’exemple illustre l’utilisation des propriétés et Item2 des Item1 propriétés pour définir une méthode qui retourne plusieurs valeurs sous la forme d’un tuple de 2 tuples.

using System;

public class Class1
{
   public static void Main()
   {
      int dividend, divisor;
      Tuple<int, int> result;
      
      dividend = 136945; divisor = 178;
      result = IntegerDivide(dividend, divisor);
      if (result != null)
         Console.WriteLine(@"{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2);
      else
         Console.WriteLine(@"{0} \ {1} = <Error>", dividend, divisor);
                        
      dividend = Int32.MaxValue; divisor = -2073;
      result = IntegerDivide(dividend, divisor);
      if (result != null)
         Console.WriteLine(@"{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2);
      else
         Console.WriteLine(@"{0} \ {1} = <Error>", dividend, divisor);
   }

   private static Tuple<int, int> IntegerDivide(int dividend, int divisor)
   {
      try {
         int remainder;
         int quotient = Math.DivRem(dividend, divisor, out remainder);
         return new Tuple<int, int>(quotient, remainder);
      }   
      catch (DivideByZeroException) {
         return null;
      }      
   }
}
// The example displays the following output:
//       136945 \ 178 = 769, remainder 63
//       2147483647 \ -2073 = -1035930, remainder 757

open System

let integerDivide (dividend: int) divisor =
    try
        let quotient, remainder = Math.DivRem(dividend, divisor)
        Tuple<int, int>(quotient, remainder)
    with :? DivideByZeroException ->
        Unchecked.defaultof<Tuple<int, int>>

[<EntryPoint>]
let main _ =
    let dividend = 136945 
    let divisor = 178
    let result = integerDivide dividend divisor
    if box result <> null then
        printfn $@"{dividend} \ {divisor} = {result.Item1}, remainder {result.Item2}" 
    else
        printfn $@"{dividend} \ {divisor} = <Error>"
                    
    let dividend = Int32.MaxValue 
    let divisor = -2073
    let result = integerDivide dividend divisor
    if box result <> null then
        printfn $@"{dividend} \ {divisor} = {result.Item1}, remainder {result.Item2}" 
    else
        printfn $@"{dividend} \ {divisor} = <Error>"
    0
// The example displays the following output:
//       136945 \ 178 = 769, remainder 63
//       2147483647 \ -2073 = -1035930, remainder 757

Module modMain
   Public Sub Main()
      Dim dividend, divisor As Integer
      Dim result As Tuple(Of Integer, Integer)
      
      dividend = 136945 : divisor = 178
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
                        
      dividend = Int32.MaxValue : divisor = -2073
      result = IntegerDivide(dividend, divisor)
      If result IsNot Nothing Then
         Console.WriteLine("{0} \ {1} = {2}, remainder {3}", 
                           dividend, divisor, result.Item1, result.Item2)
      Else
         Console.WriteLine("{0} \ {1} = <Error>", dividend, divisor)
      End If
   End Sub
   
   Private Function IntegerDivide(dividend As Integer, divisor As Integer) As Tuple(Of Integer, Integer)
      Try
         Dim remainder As Integer
         Dim quotient As Integer = Math.DivRem(dividend, divisor, remainder)
         Return New Tuple(Of Integer, Integer)(quotient, remainder)
      Catch e As DivideByZeroException
         Return Nothing
      End Try      
   End Function
End Module
' The example displays the following output:
'       136945 \ 178 = 769, remainder 63
'       2147483647 \ -2073 = -1035930, remainder 757

Remarques

Vous pouvez déterminer dynamiquement le type du Item1 composant de l’une des deux manières suivantes :

• En appelant la méthode sur la GetType valeur retournée par la Item1 propriété.

• En récupérant l’objet Type qui représente l’objet Tuple<T1,T2> et en récupérant le premier élément du tableau retourné par sa Type.GetGenericArguments méthode.