Méthode SqlGeometry.STWithin

Determines whether the current SqlGeometry is completely within the specified SqlGeometry instance.

Espace de noms :  Microsoft.SqlServer.Types
Assembly :  Microsoft.SqlServer.Types (en Microsoft.SqlServer.Types.dll)

Syntaxe

'Déclaration
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STWithin ( _
    other As SqlGeometry _
) As SqlBoolean
'Utilisation
Dim instance As SqlGeometry 
Dim other As SqlGeometry 
Dim returnValue As SqlBoolean 

returnValue = instance.STWithin(other)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STWithin(
    SqlGeometry other
)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STWithin(
    SqlGeometry^ other
)

[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STWithin : 
        other:SqlGeometry -> SqlBoolean

public function STWithin(
    other : SqlGeometry
) : SqlBoolean

Paramètres

• other
  Type : Microsoft.SqlServer.Types.SqlGeometry
  The SqlGeometry instance to compare to the current SqlGeometry.

Valeur de retour

Type : System.Data.SqlTypes.SqlBoolean
Returns true if a SqlGeometry instance is completely within another SqlGeometry instance; otherwise, returns false.

Notes

This method always returns nullune référence Null (Nothing dans Visual Basic) if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.

Voir aussi

Référence

SqlGeometry Classe

Espace de noms Microsoft.SqlServer.Types