Message.FindPartByName(String) Method

Definition

Namespace:

System.Web.Services.Description

Assembly:

System.Web.Services.dll

Searches the MessagePartCollection returned by the Parts property, and returns the named MessagePart.

public:
 System::Web::Services::Description::MessagePart ^ FindPartByName(System::String ^ partName);

public System.Web.Services.Description.MessagePart FindPartByName (string partName);

member this.FindPartByName : string -> System.Web.Services.Description.MessagePart

Public Function FindPartByName (partName As String) As MessagePart

Parameters

partName

String

A string that names the MessagePart to be returned.

Returns

MessagePart

A MessagePart.

Exceptions

ArgumentException

No MessagePart with the specified name exists within the collection.

Examples

The following example demonstrates the use of the FindPartByName method.

// Get another message from ServiceDescription.
Message^ myMessage2 = myServiceDescription->Messages[ "DivideHttpGetOut" ];
MessagePart^ myMessagePart = myMessage2->FindPartByName( "Body" );
Console::WriteLine( "Results of FindPartByName operation:" );
Console::WriteLine( "Part Name: {0}", myMessagePart->Name );
Console::WriteLine( "Part Element: {0}", myMessagePart->Element );

// Get another message from ServiceDescription.
Message myMessage2 = myServiceDescription.Messages["DivideHttpGetOut"];
MessagePart myMessagePart=myMessage2.FindPartByName("Body");
Console.WriteLine("Results of FindPartByName operation:");
Console.WriteLine("Part Name: " +myMessagePart.Name);
Console.WriteLine("Part Element: " +myMessagePart.Element);

' Get another message from ServiceDescription.
Dim myMessage2 As Message = myServiceDescription.Messages("DivideHttpGetOut")
Dim myMessagePart As MessagePart = myMessage2.FindPartByName("Body")
Console.WriteLine("Results of FindPartByName operation:")
Console.WriteLine("Part Name: " + myMessagePart.Name)
Console.WriteLine("Part Element: " + myMessagePart.Element.ToString())