नोट
इस पृष्ठ तक पहुंच के लिए प्राधिकरण की आवश्यकता होती है। आप साइन इन करने या निर्देशिकाएँ बदलने का प्रयास कर सकते हैं।
इस पृष्ठ तक पहुंच के लिए प्राधिकरण की आवश्यकता होती है। आप निर्देशिकाएँ बदलने का प्रयास कर सकते हैं।
'identifier' : is not a class or namespace name
Remarks
The language syntax requires a class, structure, union, or namespace name here.
This error can occur when you use a name that has not been declared as a class, structure, union, or namespace in front of a scope operator. To fix this issue, declare the name or include the header that declares the name before it is used.
C2653 is also possible if you try to define a compound namespace, a namespace that contains one or more scope-nested namespace names. Compound namespace definitions are not allowed in C++ prior to C++17. Compound namespaces are supported starting in Visual Studio 2015 Update 3 when you specify the /std:c++latest compiler option. Starting in Visual Studio 2017 version 15.5, the compiler supports compound namespace definitions when the /std:c++17 or later option is specified.
Examples
This example generates C2653 because a scope name is used but not declared. The compiler expects a class, structure, union, or namespace name before a scope operator (::).
// C2653.cpp
// compile with: /c
class yy {
void func1(int i);
};
void xx::func1(int m) {} // C2653, xx is not declared
void yy::func1(int m) {} // OK
In code that is not compiled for C++17 or later standards, nested namespaces must use an explicit namespace declaration at each nesting level:
// C2653b.cpp
namespace a::b {int i;} // C2653 prior to Visual Studio 2015 Update 3,
// C2429 thereafter. Use /std:c++17 or /std:c++latest to fix.
namespace a { // Use this form for conformant code under /std:c++14 (the default)
namespace b { // or when using compilers before Visual Studio 2015 update 3.
int i;
}
}
int main() {
a::b::i = 2;
}