XmlSerializer.CanDeserialize(XmlReader) Method
Definition
Important
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Gets a value that indicates whether this XmlSerializer can deserialize a specified XML document.
public:
virtual bool CanDeserialize(System::Xml::XmlReader ^ xmlReader);
public virtual bool CanDeserialize (System.Xml.XmlReader xmlReader);
abstract member CanDeserialize : System.Xml.XmlReader -> bool
override this.CanDeserialize : System.Xml.XmlReader -> bool
Public Overridable Function CanDeserialize (xmlReader As XmlReader) As Boolean
Parameters
Returns
true
if this XmlSerializer can deserialize the object that the XmlReader points to; otherwise, false
.
Examples
The following example calls the CanDeserialize method to check whether an XML document can be deserialized.
private:
void TestDocument( String^ filename, Type^ objType )
{
// Using a FileStream, create an XmlTextReader.
Stream^ fs = gcnew FileStream( filename,FileMode::Open );
XmlReader^ reader = gcnew XmlTextReader( fs );
XmlSerializer^ serializer = gcnew XmlSerializer( objType );
if ( serializer->CanDeserialize( reader ) )
{
Object^ o = serializer->Deserialize( reader );
}
fs->Close();
}
private void TestDocument(string filename, Type objType)
{
// Using a FileStream, create an XmlTextReader.
Stream fs = new FileStream(filename, FileMode.Open);
XmlReader reader = new XmlTextReader(fs);
XmlSerializer serializer = new XmlSerializer(objType);
if (serializer.CanDeserialize(reader))
{
Object o = serializer.Deserialize(reader);
}
fs.Close();
}
Private Sub TestDocument _
(ByVal filename As String, _
ByVal objType As Type)
' Using a FileStream, create an XmlTextReader.
Dim fs As New FileStream(filename, FileMode.Open)
Dim reader As New XmlTextReader(fs)
Dim serializer As New XmlSerializer(objType)
If serializer.CanDeserialize(reader) Then
Dim o As Object = serializer.Deserialize(reader)
End If
fs.Close()
End Sub
Applies to
See also
GitHub पर हमारे साथ सहयोग करें
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