Math.Sqrt(Double) Method
Definition
Important
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Returns the square root of a specified number.
public:
static double Sqrt(double d);
public static double Sqrt (double d);
static member Sqrt : double -> double
Public Shared Function Sqrt (d As Double) As Double
Parameters
- d
- Double
The number whose square root is to be found.
Returns
One of the values in the following table.
d parameter
| Return value |
---|---|
Zero or positive | The positive square root of d .
|
Negative | NaN |
Equals NaN | NaN |
Equals PositiveInfinity | PositiveInfinity |
Examples
The square root of the area of a square represents the length of any side of the square. The following example displays the area of some cities in the United States and gives an impression of each city's size if it were represented by a square.
// Create an array containing the area of some squares.
Tuple<string, double>[] areas =
{ Tuple.Create("Sitka, Alaska", 2870.3),
Tuple.Create("New York City", 302.6),
Tuple.Create("Los Angeles", 468.7),
Tuple.Create("Detroit", 138.8),
Tuple.Create("Chicago", 227.1),
Tuple.Create("San Diego", 325.2) };
Console.WriteLine("{0,-18} {1,14:N1} {2,30}\n", "City", "Area (mi.)",
"Equivalent to a square with:");
foreach (var area in areas)
Console.WriteLine("{0,-18} {1,14:N1} {2,14:N2} miles per side",
area.Item1, area.Item2, Math.Round(Math.Sqrt(area.Item2), 2));
// The example displays the following output:
// City Area (mi.) Equivalent to a square with:
//
// Sitka, Alaska 2,870.3 53.58 miles per side
// New York City 302.6 17.40 miles per side
// Los Angeles 468.7 21.65 miles per side
// Detroit 138.8 11.78 miles per side
// Chicago 227.1 15.07 miles per side
// San Diego 325.2 18.03 miles per side
open System
// Create a list containing the area of some cities.
let areas =
[ "Sitka, Alaska", 2870.3
"New York City", 302.6
"Los Angeles", 468.7
"Detroit", 138.8
"Chicago", 227.1
"San Diego", 325.2 ]
printfn "%-18s %14s} %2s\n" "City" "Area (mi.)" "Equivalent to a square with:"
for city, area in areas do
printfn $"{city,-18} {area,14:N1} {Math.Round(Math.Sqrt(area), 2),14:N2} miles per side"
// The example displays the following output:
// City Area (mi.) Equivalent to a square with:
//
// Sitka, Alaska 2,870.3 53.58 miles per side
// New York City 302.6 17.40 miles per side
// Los Angeles 468.7 21.65 miles per side
// Detroit 138.8 11.78 miles per side
// Chicago 227.1 15.07 miles per side
// San Diego 325.2 18.03 miles per side
Module Example
Public Sub Main()
' Create an array containing the area of some squares.
Dim areas() As Tuple(Of String, Double) =
{ Tuple.Create("Sitka, Alaska", 2870.3),
Tuple.Create("New York City", 302.6),
Tuple.Create("Los Angeles", 468.7),
Tuple.Create("Detroit", 138.8),
Tuple.Create("Chicago", 227.1),
Tuple.Create("San Diego", 325.2) }
Console.WriteLine("{0,-18} {1,14:N1} {2,30}", "City", "Area (mi.)",
"Equivalent to a square with:")
Console.WriteLine()
For Each area In areas
Console.WriteLine("{0,-18} {1,14:N1} {2,14:N2} miles per side",
area.Item1, area.Item2, Math.Round(Math.Sqrt(area.Item2), 2))
Next
End Sub
End Module
' The example displays the following output:
' City Area (mi.) Equivalent to a square with:
'
' Sitka, Alaska 2,870.3 53.58 miles per side
' New York City 302.6 17.40 miles per side
' Los Angeles 468.7 21.65 miles per side
' Detroit 138.8 11.78 miles per side
' Chicago 227.1 15.07 miles per side
' San Diego 325.2 18.03 miles per side
Applies to
See also
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