Complex.Abs(Complex) Method
Definition
Important
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Gets the absolute value (or magnitude) of a complex number.
public:
static double Abs(System::Numerics::Complex value);
public static double Abs (System.Numerics.Complex value);
static member Abs : System.Numerics.Complex -> double
Public Shared Function Abs (value As Complex) As Double
Parameters
- value
- Complex
A complex number.
Returns
The absolute value of value
.
Examples
The following example calculates the absolute value of a complex number and demonstrates that it is equivalent to the value of the Magnitude property.
using System;
using System.Numerics;
public class Example
{
public static void Main()
{
Complex complex1 = new Complex(2.0, 3.0);
Console.WriteLine("|{0}| = {1:N2}", complex1, Complex.Abs(complex1));
Console.WriteLine("Equal to Magnitude: {0}",
Complex.Abs(complex1).Equals(complex1.Magnitude));
}
}
// The example displays the following output:
// |(2, 3)| = 3.61
// Equal to Magnitude: True
open System.Numerics
let complex1 = Complex(2., 3.)
printfn $"|{complex1}| = {Complex.Abs complex1:N2}"
printfn $"Equal to Magnitude: {Complex.Abs(complex1).Equals complex1.Magnitude}"
// The example displays the following output:
// |(2, 3)| = 3.61
// Equal to Magnitude: True
Remarks
The absolute value of a complex number is equivalent to its Magnitude property. The absolute value of a complex number a + bi
is calculated as follows:
- If
b = 0
, the result isa
. - If
a > b
, the result is $a \times \sqrt{1 + \frac{b^2}{a^2}}$. - If
b > a
, the result is $b \times \sqrt{1 + \frac{a^2}{b^2}}$.
If the calculation of the absolute value results in an overflow, the method returns either Double.PositiveInfinity or Double.NegativeInfinity. If either the Real or Imaginary property is Double.NaN and the other property is neither Double.PositiveInfinity nor Double.NegativeInfinity, the method returns Double.NaN.