XmlIncludeAttribute.Type Tulajdonság

Definíció

Névtér:

System.Xml.Serialization

Szerelvények:

netstandard.dll, System.Xml.XmlSerializer.dll

Forrás:

XmlIncludeAttribute.cs

Lekéri vagy beállítja a belefoglalandó objektum típusát.

public:
 property Type ^ Type { Type ^ get(); void set(Type ^ value); };

public Type? Type { get; set; }

member this.Type : Type with get, set

Public Property Type As Type

Tulajdonság értéke

Type

A Type belefoglalandó objektum.

Példák

Az alábbi példa egy osztályt Grouphatároz meg, amely egy objektumtömböt Employees visszaadó mezőt Employee tartalmaz. A példa az osztályt az ManagerEmployee osztályból származtatja, és az XmlIncludeAttribute osztályra Employee alkalmazza. Amikor a példa létrehoz egy Group objektumot, beszúr egy Manager objektumot a Employee tömbbe. Végül a példa szerializálja az Group objektumot.

using System;
using System.IO;
using System.Xml.Serialization;

public class Group
{
   public Employee[] Employees;
}

// Instruct the XmlSerializer to accept Manager types as well.
[XmlInclude(typeof(Manager))]
public class Employee
{
   public string Name;
}

public class Manager:Employee
{
   public int Level;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.SerializeObject("IncludeExample.xml");
      test.DeserializeObject("IncludeExample.xml");
   }

   public void SerializeObject(string filename)
   {
      XmlSerializer s = new XmlSerializer(typeof(Group));
      TextWriter writer = new StreamWriter(filename);
      Group group = new Group();

      Manager manager = new Manager();
      Employee emp1 = new Employee();
      Employee emp2 = new Employee();

      manager.Name = "Zeus";
      manager.Level = 2;

      emp1.Name = "Ares";

      emp2.Name = "Artemis";

      Employee [] emps = new Employee[3]{manager, emp1, emp2};
      group.Employees = emps;

      s.Serialize(writer, group);
      writer.Close();
   }

   public void DeserializeObject(string filename)
   {
      FileStream fs = new FileStream(filename, FileMode.Open);
      XmlSerializer x = new XmlSerializer(typeof(Group));
      Group g = (Group) x.Deserialize(fs);
      Console.Write("Members:");

      foreach(Employee e in g.Employees)
      {
         Console.WriteLine("\t" + e.Name);
      }
   }
}

Imports System.IO
Imports System.Xml.Serialization

Public Class Group
    Public Employees() As Employee
End Class

' Instruct the XmlSerializer to accept Manager types as well.
<XmlInclude(GetType(Manager))> _
Public Class Employee
    Public Name As String
End Class

Public Class Manager
    Inherits Employee
    Public Level As Integer
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("IncludeExample.xml")
        test.DeserializeObject("IncludeExample.xml")
    End Sub    
    
    
    Public Sub SerializeObject(ByVal filename As String)
        Dim s As New XmlSerializer(GetType(Group))
        Dim writer As New StreamWriter(filename)
        Dim group As New Group()
        
        Dim manager As New Manager()
        Dim emp1 As New Employee()
        Dim emp2 As New Employee()
        
        manager.Name = "Zeus"
        manager.Level = 2
        
        emp1.Name = "Ares"
        
        emp2.Name = "Artemis"
        
        Dim emps() As Employee = {manager, emp1, emp2}
        group.Employees = emps
        
        s.Serialize(writer, group)
        writer.Close()
    End Sub    
    
    Public Sub DeserializeObject(ByVal filename As String)
        Dim fs As New FileStream(filename, FileMode.Open)
        Dim x As New XmlSerializer(GetType(Group))
        Dim g As Group = CType(x.Deserialize(fs), Group)
        Console.Write("Members:")
        
        Dim e As Employee
        For Each e In  g.Employees
            Console.WriteLine(ControlChars.Tab + e.Name)
        Next e
    End Sub
End Class