set::operator=
Replaces the elements of this set using elements from another set.
set& operator=(
const set& _Right
);
set& operator=(
set&& _Right
);
Parameters
Parameter |
Description |
_Right |
The set providing new elements to be assigned to this set. |
Remarks
The first version of operator= uses an lvalue reference for _Right, to copy elements from _Right to this set.
The second version uses an rvalue reference for _Right. It moves elements from _Right to this set.
Any elements in this set before the operator function executes are discarded.
Example
// set_operator_as.cpp
// compile with: /EHsc
#include <set>
#include <iostream>
int main( )
{
using namespace std;
set<int> v1, v2, v3;
set<int>::iterator iter;
v1.insert(10);
cout << "v1 = " ;
for (iter = v1.begin(); iter != v1.end(); iter++)
cout << *iter << " ";
cout << endl;
v2 = v1;
cout << "v2 = ";
for (iter = v2.begin(); iter != v2.end(); iter++)
cout << *iter << " ";
cout << endl;
// move v1 into v2
v2.clear();
v2 = move(v1);
cout << "v2 = ";
for (iter = v2.begin(); iter != v2.end(); iter++)
cout << *iter << " ";
cout << endl;
}
Output
v1 = 10
v2 = 10
v2 = 10
Requirements
Header: <set>
Namespace: std