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InOutArgument<T>.FromExpression Metode

Definisi

Menginisialisasi dan mengembalikan yang baru InOutArgument<T> dibangun menggunakan yang ditentukan Activity<TResult>.

public:
 static System::Activities::InOutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.InOutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.InOutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As InOutArgument(Of T)

Parameter

expression
Activity<Location<T>>

Nilai argumen.

Mengembalikan

Argumen baru.

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