dayofyear

Extract the day of the year of a given date/timestamp as integer.

For the corresponding Databricks SQL function, see dayofyear function.

Syntax

from pyspark.sql import functions as dbf

dbf.dayofyear(col=<col>)

Parameters

Parameter	Type	Description
col	pyspark.sql.Column or str	target date/timestamp column to work on.

Returns

pyspark.sql.Column: day of the year for given date/timestamp as integer.

Examples

from pyspark.sql import functions as dbf
df = spark.createDataFrame([('2015-04-08',), ('2024-10-31',)], ['dt'])
df.select("*", dbf.typeof('dt'), dbf.dayofyear('dt')).show()
df = spark.createDataFrame([('2015-04-08 13:08:15',), ('2024-10-31 10:09:16',)], ['ts'])
df.select("*", dbf.typeof('ts'), dbf.dayofyear('ts')).show()
import datetime
df = spark.createDataFrame([
(datetime.date(2015, 4, 8),),
(datetime.date(2024, 10, 31),)], ['dt'])
df.select("*", dbf.typeof('dt'), dbf.dayofyear('dt')).show()
import datetime
df = spark.createDataFrame([
(datetime.datetime(2015, 4, 8, 13, 8, 15),),
(datetime.datetime(2024, 10, 31, 10, 9, 16),)], ['ts'])
df.select("*", dbf.typeof('ts'), dbf.dayofyear('ts')).show()