__ll_rshift
Microsoft Specific
Shifts a 64-bit value specified by the first parameter to the right, by a number of bits specified by the second parameter.
Syntax
__int64 __ll_rshift(
__int64 Mask,
int nBit
);
Parameters
Mask
[in] The 64-bit integer value to shift right.
nBit
[in] The number of bits to shift, modulo 64 on x64, and modulo 32 on x86.
Return value
The mask shifted by nBit bits.
Requirements
| Intrinsic | Architecture |
|---|---|
__ll_rshift |
x86, x64 |
Header file <intrin.h>
Remarks
If the second parameter is greater than 64 on x64 (32 on x86), that number is taken modulo 64 (32 on x86) to determine the number of bits to shift. The ll prefix indicates that it's an operation on long long, another name for __int64, the 64-bit signed integral type.
Example
// ll_rshift.cpp
// compile with: /EHsc
// processor: x86, x64
#include <iostream>
#include <intrin.h>
using namespace std;
#pragma intrinsic(__ll_rshift)
int main()
{
__int64 Mask = - 0x100;
int nBit = 4;
cout << hex << Mask << endl;
cout << " - " << (- Mask) << endl;
Mask = __ll_rshift(Mask, nBit);
cout << hex << Mask << endl;
cout << " - " << (- Mask) << endl;
}
Output
ffffffffffffff00
- 100
fffffffffffffff0
- 10
Note
If _ull_rshift has been used, the MSB of the right-shifted value would have been zero, so the desired result would not have been obtained in the case of a negative value.
END Microsoft Specific