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VCALinkTool.OutputBaseFileName Property

Definition

Gets the name (but not the location) of the generated satellite resource DLL or DLL.

public:
 property System::String ^ OutputBaseFileName { System::String ^ get(); };
public:
 property Platform::String ^ OutputBaseFileName { Platform::String ^ get(); };
[System.Runtime.InteropServices.DispId(4)]
public string OutputBaseFileName { [System.Runtime.InteropServices.DispId(4)] get; }
[<System.Runtime.InteropServices.DispId(4)>]
[<get: System.Runtime.InteropServices.DispId(4)>]
member this.OutputBaseFileName : string
Public ReadOnly Property OutputBaseFileName As String

Property Value

The name of the generated satellite resource DLL.

Attributes

Examples

' Add a reference to Microsoft.VisualStudio.VCProjectEngine and have a   
' Visual C++ project loaded before running this example.  
Imports EnvDTE  
Imports Microsoft.VisualStudio.VCProjectEngine  
Public Module Module1  
    Sub Test()  
        Dim prj As VCProject  
        Dim cfgs, tools As IVCCollection  
        Dim cfg As VCConfiguration  
        Dim tool As VCALinkTool  
        prj = DTE.Solution.Projects.Item(1).Object  
        cfgs = prj.Configurations  
        cfg = cfgs.Item(1)  
        tool = cfg.Tools("VCALinkTool")  
        MsgBox("Output base file name: " & tool.OutputBaseFileName)  
    End Sub  
End Module  

Remarks

The common language runtime, which requires that satellite resources have the same name, are distinguished by their directories. For example, French resources would have the name specified here and be in a subdirectory named "fr" under the directory in which the primary output resides. As a result, the name returned by OutputBaseFileName is always a single name, even when there are multiple satellite DLLs being generated.

See How to: Compile Example Code for Project Model Extensibility for information about how to compile and run this sample.

Applies to