Uri.HostNameType プロパティ

定義

名前空間:

System

アセンブリ:

System.Runtime.dll

アセンブリ:

System.dll

アセンブリ:

netstandard.dll

URI に指定したホスト名の型を取得します。

public:
 property UriHostNameType HostNameType { UriHostNameType get(); };

public UriHostNameType HostNameType { get; }

member this.HostNameType : UriHostNameType

Public ReadOnly Property HostNameType As UriHostNameType

プロパティ値

UriHostNameType

UriHostNameType 列挙体のメンバー。

例外

InvalidOperationException

このインスタンスは相対 URI を表します。このプロパティは、絶対 URI でのみ有効です。

例

次の例では、インスタンスを Uri 作成し、 HostNameType コンソールに書き込みます。

Uri^ address1 = gcnew Uri( "http://www.contoso.com/index.htm#search" );
Console::WriteLine( "address 1 {0} a valid scheme name",
   Uri::CheckSchemeName( address1->Scheme ) ? (String^)" has" : " does not have" );
if ( address1->Scheme == Uri::UriSchemeHttp )
{
   Console::WriteLine( "Uri is HTTP type" );
}

Console::WriteLine( address1->HostNameType );

Uri address1 = new Uri("http://www.contoso.com/index.htm#search");
Console.WriteLine("address 1 {0} a valid scheme name",
      Uri.CheckSchemeName(address1.Scheme) ? " has" : " does not have");

if (address1.Scheme == Uri.UriSchemeHttp)
    Console.WriteLine("Uri is HTTP type");

Console.WriteLine(address1.HostNameType);

let address1 = Uri "http://www.contoso.com/index.htm#search"
printfn $"""address 1 {if Uri.CheckSchemeName address1.Scheme then " has" else " does not have"} a valid scheme name"""

if address1.Scheme = Uri.UriSchemeHttp then
    printfn "Uri is HTTP type"

printfn $"{address1.HostNameType}"

Dim address1 As New Uri("http://www.contoso.com/index.htm#search")
Console.WriteLine("address 1 {0} a valid scheme name", IIf(Uri.CheckSchemeName(address1.Scheme), " has", " does not have")) 'TODO: For performance reasons this should be changed to nested IF statements

If address1.Scheme = Uri.UriSchemeHttp Then
    Console.WriteLine("Uri is HTTP type")
End If 
Console.WriteLine(address1.HostNameType)