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XmlArrayItemAttribute Конструкторы

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Определение

Пространство имен:
System.Xml.Serialization
Сборка:
System.Xml.XmlSerializer.dll
Сборка:
System.Xml.dll
Сборка:
netstandard.dll

Инициализирует новый экземпляр класса XmlArrayItemAttribute.

Перегрузки

XmlArrayItemAttribute()

Инициализирует новый экземпляр класса XmlArrayItemAttribute.
XmlArrayItemAttribute(String)

Инициализация нового экземпляра класса XmlArrayItemAttribute и указывает имя элемента XML, сгенерированного в документе XML.
XmlArrayItemAttribute(Type)

Инициализация нового экземпляра класса XmlArrayItemAttribute и определяет Type, который может быть вставлен в сериализованный массив.
XmlArrayItemAttribute(String, Type)

Инициализация нового экземпляра класса XmlArrayItemAttribute и определяет имя элемента XML, сгенерированного в документе XML, и Type, который может быть вставлен в сгенерированный документ XML.

XmlArrayItemAttribute()

Инициализирует новый экземпляр класса XmlArrayItemAttribute.

public:
 XmlArrayItemAttribute();
public XmlArrayItemAttribute ();
Public Sub New ()

Примеры

В следующем примере сериализуется класс с именем Transportation , содержащий поле с именем MyVehicles , которое возвращает массив Vehicle объектов. Пример применяется XmlArrayItemAttribute к полю, что позволяет XmlSerializer вставлять экземпляры Car класса, производные от Vehicle класса, в массив.

#using <System.Xml.dll>
#using <System.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;

public ref class Vehicle
{
public:
   String^ id;
};

public ref class Car: public Vehicle
{
public:
   String^ Maker;
};

public ref class Transportation
{
public:

   [XmlArrayItem,
   XmlArrayItem(Car::typeid,ElementName="Automobile")]
   array<Vehicle^>^MyVehicles;
};

void SerializeObject( String^ filename )
{
   // Creates an XmlSerializer for the Transportation class. 
   XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );

   // Writing the XML file to disk requires a TextWriter.
   TextWriter^ myTextWriter = gcnew StreamWriter( filename );

   // Creates the object to serialize.
   Transportation^ myTransportation = gcnew Transportation;

   // Creates objects to add to the array.
   Vehicle^ myVehicle = gcnew Vehicle;
   myVehicle->id = "A12345";
   Car^ myCar = gcnew Car;
   myCar->id = "Car 34";
   myCar->Maker = "FamousCarMaker";
   array<Vehicle^>^temp = {myVehicle,myCar};
   myTransportation->MyVehicles = temp;

   // Serializes the object, and closes the StreamWriter.
   MySerializer->Serialize( myTextWriter, myTransportation );
   myTextWriter->Close();
}

void DeserializeObject( String^ filename )
{
   // Creates an XmlSerializer instance.
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
   FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
   Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
   for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
   {
      Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
   }
}

int main()
{
   SerializeObject( "XmlArrayItem1.xml" );
   DeserializeObject( "XmlArrayItem1.xml" );
}

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test = new Run();
      test.SerializeObject("XmlArrayItem1.xml");
      test.DeserializeObject("XmlArrayItem1.xml");
   }

   private void SerializeObject(string filename){
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer = new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      // Creates the object to serialize.
      Transportation myTransportation = new Transportation();

      // Creates objects to add to the array.
      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      myTransportation.MyVehicles =
      new Vehicle[2] {myVehicle, myCar};

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer instance.
      XmlSerializer mySerializer = new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0; i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
 }

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem1.xml")
        test.DeserializeObject("XmlArrayItem1.xml")
    End Sub
    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        ' Creates the object to serialize.
        Dim myTransportation As New Transportation()
        
        ' Creates objects to add to the array.
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        myTransportation.MyVehicles = New Vehicle() {myVehicle, myCar}
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create an XmlSerializer instance.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Применяется к

XmlArrayItemAttribute(String)

Инициализация нового экземпляра класса XmlArrayItemAttribute и указывает имя элемента XML, сгенерированного в документе XML.

public:
 XmlArrayItemAttribute(System::String ^ elementName);
public XmlArrayItemAttribute (string elementName);
public XmlArrayItemAttribute (string? elementName);
new System.Xml.Serialization.XmlArrayItemAttribute : string -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String)

Параметры

elementName
String

Имя элемента XML.

Примеры

В следующем примере сериализуется класс с именем Transportation , содержащий поле с именем MyVehicles , которое возвращает массив Vehicle объектов. Пример применяется XmlArrayItemAttribute к полю, что позволяет XmlSerializer вставлять экземпляры Car класса, производные от Vehicle класса, в массив. При применении атрибута в примере задается ElementName свойство с помощью elementName параметра.

#using <System.Xml.dll>
#using <System.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;

public ref class Vehicle
{
public:
   String^ id;
};

public ref class Car: public Vehicle
{
public:
   String^ Maker;
};

public ref class Transportation
{
public:

   [XmlArrayItem(ElementName="Transportation"),
   XmlArrayItem(Car::typeid,ElementName="Automobile")]
   array<Vehicle^>^MyVehicles;
};

void SerializeObject( String^ filename )
{
   // Creates an XmlSerializer for the Transportation class.
   XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );

   // Writing the XML file to disk requires a TextWriter.
   TextWriter^ myTextWriter = gcnew StreamWriter( filename );
   Transportation^ myTransportation = gcnew Transportation;
   Vehicle^ myVehicle = gcnew Vehicle;
   myVehicle->id = "A12345";
   Car^ myCar = gcnew Car;
   myCar->id = "Car 34";
   myCar->Maker = "FamousCarMaker";
   array<Vehicle^>^myVehicles = {myVehicle,myCar};
   myTransportation->MyVehicles = myVehicles;

   // Serializes the object, and closes the StreamWriter.
   MySerializer->Serialize( myTextWriter, myTransportation );
   myTextWriter->Close();
}

void DeserializeObject( String^ filename )
{
   // Creates the serializer with the type to deserialize.
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
   FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
   Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
   for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
   {
      Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
   }
}

int main()
{
   SerializeObject( "XmlArrayItem2.xml" );
   DeserializeObject( "XmlArrayItem2.xml" );
}

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(ElementName = "Transportation"),
   XmlArrayItem(typeof(Car), ElementName = "Automobile")]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem2.xml");
      test.DeserializeObject("XmlArrayItem2.xml");
   }

   private void SerializeObject(string filename)
   {
      // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(ElementName := "Transportation"), _
     XmlArrayItem(GetType(Car), ElementName := "Automobile")> _
    Public MyVehicles() As Vehicle
End Class

Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem2.xml")
        test.DeserializeObject("XmlArrayItem2.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle = {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub
        
    Private Sub DeserializeObject(ByVal filename As String)
        ' Create the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Комментарии

Эта перегрузка ElementName задает свойство.

Используйте эту перегрузку, если требуется, чтобы имя созданного XML-элемента отличалось от идентификатора элемента.

XML-документ, включающий пространства имен, может содержать несколько версий имени элемента. Дополнительные сведения см. в свойстве ElementName.

Применяется к

XmlArrayItemAttribute(Type)

Инициализация нового экземпляра класса XmlArrayItemAttribute и определяет Type, который может быть вставлен в сериализованный массив.

public:
 XmlArrayItemAttribute(Type ^ type);
public XmlArrayItemAttribute (Type type);
public XmlArrayItemAttribute (Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (type As Type)

Параметры

type
Type

Тип Type сериализуемого объекта.

Примеры

В следующем примере сериализуется класс с именем Transportation , содержащий поле с именем MyVehicles , которое возвращает массив Vehicle объектов. Пример применяется XmlArrayItemAttribute к полю, что позволяет XmlSerializer вставлять экземпляры Car класса, производные от Vehicle класса, в массив. При применении атрибута в примере задается Type свойство с помощью type параметра.

#using <System.Xml.dll>
#using <System.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;

public ref class Vehicle
{
public:
   String^ id;
};

public ref class Car: public Vehicle
{
public:
   String^ Maker;
};

public ref class Transportation
{
public:

   [XmlArrayItem(Vehicle::typeid),
   XmlArrayItem(Car::typeid)]
   array<Vehicle^>^MyVehicles;
};

void SerializeObject( String^ filename )
{
   // Creates an XmlSerializer. 
   XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );

   // Writing the XML file to disk requires a TextWriter.
   TextWriter^ myTextWriter = gcnew StreamWriter( filename );
   Transportation^ myTransportation = gcnew Transportation;
   Vehicle^ myVehicle = gcnew Vehicle;
   myVehicle->id = "A12345";
   Car^ myCar = gcnew Car;
   myCar->id = "Car 34";
   myCar->Maker = "FamousCarMaker";
   array<Vehicle^>^myVehicles = {myVehicle,myCar};
   myTransportation->MyVehicles = myVehicles;

   // Serializes the object, and closes the StreamWriter.
   MySerializer->Serialize( myTextWriter, myTransportation );
   myTextWriter->Close();
}

void DeserializeObject( String^ filename )
{
   // Creates the serializer with the type to deserialize.
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
   FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
   Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
   for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
   {
      Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
   }
}

int main()
{
   SerializeObject( "XmlArrayItem3.xml" );
   DeserializeObject( "XmlArrayItem3.xml" );
}

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArrayItem(typeof(Vehicle)),
   XmlArrayItem(typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem3.xml");
      test.DeserializeObject("XmlArrayItem3.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates the serializer with the type to deserialize.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArrayItem(GetType(Vehicle)), _
     XmlArrayItem(GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem3.xml")
        test.DeserializeObject("XmlArrayItem3.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer object. 
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates the serializer with the type to deserialize.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Применяется к

XmlArrayItemAttribute(String, Type)

Инициализация нового экземпляра класса XmlArrayItemAttribute и определяет имя элемента XML, сгенерированного в документе XML, и Type, который может быть вставлен в сгенерированный документ XML.

public:
 XmlArrayItemAttribute(System::String ^ elementName, Type ^ type);
public XmlArrayItemAttribute (string elementName, Type type);
public XmlArrayItemAttribute (string? elementName, Type? type);
new System.Xml.Serialization.XmlArrayItemAttribute : string * Type -> System.Xml.Serialization.XmlArrayItemAttribute
Public Sub New (elementName As String, type As Type)

Параметры

elementName
String

Имя элемента XML.

type
Type

Тип Type сериализуемого объекта.

Примеры

В следующем примере сериализуется класс с именем Transportation , содержащий поле с именем MyVehicles , которое возвращает массив Vehicle объектов. Пример применяется XmlArrayItemAttribute к полю, что позволяет XmlSerializer вставлять экземпляры Car класса, производные от Vehicle класса, в массив. При применении атрибута пример задает ElementName свойство с помощью elementName параметра и Type свойство с помощью type параметра.

#using <System.Xml.dll>
#using <System.dll>

using namespace System;
using namespace System::IO;
using namespace System::Xml;
using namespace System::Xml::Serialization;

public ref class Vehicle
{
public:
   String^ id;
};

public ref class Car: public Vehicle
{
public:
   String^ Maker;
};

public ref class Transportation
{
public:

   [XmlArray]
   [XmlArrayItem("Transport",Vehicle::typeid),
   XmlArrayItem("Automobile",Car::typeid)]
   array<Vehicle^>^MyVehicles;
};

void SerializeObject( String^ filename )
{
   // Creates an XmlSerializer for the Transportation class.
   XmlSerializer^ MySerializer = gcnew XmlSerializer( Transportation::typeid );

   // Writing the XML file to disk requires a TextWriter.
   TextWriter^ myTextWriter = gcnew StreamWriter( filename );
   Transportation^ myTransportation = gcnew Transportation;
   Vehicle^ myVehicle = gcnew Vehicle;
   myVehicle->id = "A12345";
   Car^ myCar = gcnew Car;
   myCar->id = "Car 34";
   myCar->Maker = "FamousCarMaker";
   array<Vehicle^>^myVehicles = {myVehicle,myCar};
   myTransportation->MyVehicles = myVehicles;

   // Serializes the object, and closes the StreamWriter.
   MySerializer->Serialize( myTextWriter, myTransportation );
   myTextWriter->Close();
}

void DeserializeObject( String^ filename )
{
   // Creates an XmlSerializer.
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Transportation::typeid );
   FileStream^ myFileStream = gcnew FileStream( filename,FileMode::Open );
   Transportation^ myTransportation = dynamic_cast<Transportation^>(mySerializer->Deserialize( myFileStream ));
   for ( int i = 0; i < myTransportation->MyVehicles->Length; i++ )
   {
      Console::WriteLine( myTransportation->MyVehicles[ i ]->id );
   }
}

int main()
{
   SerializeObject( "XmlArrayItem4.xml" );
   DeserializeObject( "XmlArrayItem4.xml" );
}

using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;

public class Vehicle
{
   public string id;
}
public class Car:Vehicle
{
   public string Maker;
}

public class Transportation
{
   [XmlArray]
   [XmlArrayItem("Transport", typeof(Vehicle)),
   XmlArrayItem("Automobile", typeof(Car))]
   public Vehicle[] MyVehicles;
}

public class Run
{
   public static void Main()
   {
      Run test= new Run();
      test.SerializeObject("XmlArrayItem4.xml");
      test.DeserializeObject("XmlArrayItem4.xml");
   }

   private void SerializeObject(string filename)
   {
       // Creates an XmlSerializer for the Transportation class.
      XmlSerializer MySerializer =
      new XmlSerializer(typeof(Transportation));

      // Writing the XML file to disk requires a TextWriter.
      TextWriter myTextWriter = new StreamWriter(filename);

      Transportation myTransportation = new Transportation();

      Vehicle myVehicle= new Vehicle() ;
      myVehicle.id = "A12345";

      Car myCar = new Car();
      myCar.id = "Car 34";
      myCar.Maker = "FamousCarMaker";

      Vehicle [] myVehicles = {myVehicle, myCar};
      myTransportation.MyVehicles = myVehicles;

      // Serializes the object, and closes the StreamWriter.
      MySerializer.Serialize(myTextWriter, myTransportation);
      myTextWriter.Close();
   }

   private void DeserializeObject(string filename)
   {
      // Creates an XmlSerializer.
      XmlSerializer mySerializer =
      new XmlSerializer(typeof(Transportation));
      FileStream myFileStream = new FileStream(filename,FileMode.Open);
      Transportation myTransportation =
      (Transportation) mySerializer.Deserialize(myFileStream);

      for(int i = 0;i < myTransportation.MyVehicles.Length;i++)
      {
         Console.WriteLine(myTransportation.MyVehicles[i].id);
      }
   }
}

Option Explicit
Option Strict

Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization


Public Class Vehicle
    Public id As String
End Class

Public Class Car
    Inherits Vehicle
    Public Maker As String
End Class

Public Class Transportation
    <XmlArray(), _
     XmlArrayItem("Transport", GetType(Vehicle)), _
     XmlArrayItem("Automobile", GetType(Car))> _
    Public MyVehicles() As Vehicle
End Class


Public Class Run
    
    Public Shared Sub Main()
        Dim test As New Run()
        test.SerializeObject("XmlArrayItem4.xml")
        test.DeserializeObject("XmlArrayItem4.xml")
    End Sub    
    
    Private Sub SerializeObject(ByVal filename As String)
        ' Creates an XmlSerializer for the Transportation class.
        Dim MySerializer As New XmlSerializer(GetType(Transportation))
        
        ' Writing the XML file to disk requires a TextWriter.
        Dim myTextWriter As New StreamWriter(filename)
        
        Dim myTransportation As New Transportation()
        
        Dim myVehicle As New Vehicle()
        myVehicle.id = "A12345"
        
        Dim myCar As New Car()
        myCar.id = "Car 34"
        myCar.Maker = "FamousCarMaker"
        
        Dim myVehicles() As Vehicle =  {myVehicle, myCar}
        myTransportation.MyVehicles = myVehicles
        
        ' Serializes the object, and closes the StreamWriter.
        MySerializer.Serialize(myTextWriter, myTransportation)
        myTextWriter.Close()
    End Sub    
    
    Private Sub DeserializeObject(ByVal filename As String)
        ' Creates an XmlSerializer.
        Dim mySerializer As New XmlSerializer(GetType(Transportation))
        Dim myFileStream As New FileStream(filename, FileMode.Open)
        Dim myTransportation As Transportation = _
            CType(mySerializer.Deserialize(myFileStream), Transportation)
        
        Dim i As Integer
        For i = 0 To myTransportation.MyVehicles.Length - 1
            Console.WriteLine(myTransportation.MyVehicles(i).id)
        Next i
    End Sub
End Class

Комментарии

Эта перегрузка задает ElementName свойства и Type свойства.

Используйте эту перегрузку, если требуется, чтобы имя созданного XML-элемента отличалось от идентификатора элемента.

XML-документ, включающий пространства имен, может содержать несколько версий имени элемента. Дополнительные сведения см. в свойстве ElementName.

Применяется к