PointF.Equality(PointF, PointF) 연산자

정의

네임스페이스:
System.Drawing
어셈블리:
netstandard.dll, System.Drawing.Primitives.dll
어셈블리:
System.Drawing.Primitives.dll
어셈블리:
System.Drawing.dll
어셈블리:
netstandard.dll
Source:
PointF.cs
Source:
PointF.cs
Source:
PointF.cs
Source:
PointF.cs
Source:
PointF.cs

두 PointF 구조를 비교합니다. 결과는 두 X 구조체의 Y 값과 PointF 속성이 같은지 여부를 지정합니다.

public:
 static bool operator ==(System::Drawing::PointF left, System::Drawing::PointF right);
public static bool operator ==(System.Drawing.PointF left, System.Drawing.PointF right);
static member ( = ) : System.Drawing.PointF * System.Drawing.PointF -> bool
Public Shared Operator == (left As PointF, right As PointF) As Boolean

매개 변수

left
PointF

비교할 A PointF 입니다.

right
PointF

비교할 A PointF 입니다.

반품

Boolean

true X 왼쪽 및 오른쪽 Y 구조체의 값과 PointF 값이 같으면 이고, false그렇지 않으면 .

예제

다음 코드 예제에서는 연산자를 사용하는 방법을 보여 줍니다 Equality . 이 예제를 실행하려면 다음 코드를 Windows Form에 붙여넣습니다. 양식의 Paint 이벤트를 처리하고 호출opAdditionExample하여 다음으로 e전달 PaintEventArgs 합니다.

private void OpAdditionExample(PaintEventArgs e)
{
    PointF point1 = new PointF(120.5F, 120F);
    SizeF size1 = new SizeF(120.5F, 30.5F);
    RectangleF rect1 = new RectangleF(point1, size1);
    if (new PointF(rect1.Right, rect1.Bottom) == point1 + size1)
        e.Graphics.DrawString("They are equal", this.Font, Brushes.Black, rect1);
    else
        e.Graphics.DrawString("They are not equal", this.Font, Brushes.Red, rect1);
}

Private Sub OpAdditionExample(ByVal e As PaintEventArgs) 
    Dim size1 As New SizeF(120.5F, 30.5F)
    Dim point1 As New PointF(20.5F, 20F)
    Dim rect1 As New RectangleF(point1, size1)
    If New PointF(rect1.Right, rect1.Bottom) = point1 + size1 Then
        e.Graphics.DrawString("They are equal", Me.Font, Brushes.Black, rect1)
    Else
        e.Graphics.DrawString("They are not equal", Me.Font, Brushes.Red, rect1)
    End If
 
End Sub

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