XObject.NodeType Property
Definition
Important
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Gets the node type for this XObject.
public:
abstract property System::Xml::XmlNodeType NodeType { System::Xml::XmlNodeType get(); };
public abstract System.Xml.XmlNodeType NodeType { get; }
member this.NodeType : System.Xml.XmlNodeType
Public MustOverride ReadOnly Property NodeType As XmlNodeType
Property Value
The node type for this XObject.
Examples
The following example uses this method to retrieve the node type for a variety of nodes.
// Note that XNode uses XmlNodeType, which is in the System.Xml namespace.
XDocument xmlTree = new XDocument(
new XComment("a comment"),
new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),
new XElement("Root",
new XAttribute("Att", "attContent"),
new XElement("Child1",
new XCData("CDATA content")
),
new XElement("Child2",
new XText("Text content")
)
)
);
foreach (XNode node in xmlTree.DescendantNodes())
{
Console.WriteLine(node.NodeType);
if (node.NodeType == XmlNodeType.Element)
{
foreach (XAttribute att in ((XElement)node).Attributes())
Console.WriteLine(att.NodeType);
}
}
' Note that XNode uses XmlNodeType, which is in the System.Xml namespace.
Dim xmlTree As XDocument = _
<?xml version="1.0"?>
<!--a comment-->
<?xml-stylesheet type="text/xsl" href="hello.xsl"?>
<Root Att="attContent">
<Child1><![CDATA[CDATA content]]></Child1>
<Child2>Text content</Child2>
</Root>
For Each node As XNode In xmlTree.DescendantNodes
Console.WriteLine(node.NodeType.ToString())
If node.NodeType = XmlNodeType.Element Then
For Each att In DirectCast(node, XElement).Attributes
Console.WriteLine(att.NodeType.ToString())
Next
End If
Next
This example produces the following output:
Comment
ProcessingInstruction
Element
Attribute
Element
CDATA
Element
Text
Remarks
Because all classes that derive from XObject contain a NodeType property, you can write code that operates on collections of concrete subclass of XObject. Your code can then test for the node type of each node in the collection.
Applies to
See also
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