XmlChoiceIdentifierAttribute.MemberName 속성

참조

정의

네임스페이스:: System.Xml.Serialization

어셈블리:: System.Xml.XmlSerializer.dll

어셈블리:: System.Xml.dll

어셈블리:: netstandard.dll

중요

일부 정보는 릴리스되기 전에 상당 부분 수정될 수 있는 시험판 제품과 관련이 있습니다. Microsoft는 여기에 제공된 정보에 대해 어떠한 명시적이거나 묵시적인 보증도 하지 않습니다.

형식을 검색하는 경우 사용할 열거형을 반환하는 필드의 이름을 가져오거나 설정합니다.

public:
 property System::String ^ MemberName { System::String ^ get(); void set(System::String ^ value); };

public string MemberName { get; set; }

member this.MemberName : string with get, set

Public Property MemberName As String

속성 값

String

열거형을 반환하는 필드의 이름입니다.

예제

다음 예제에서는 두 개의 필드를 포함하는 클래스 Choices 를 직렬화합니다ManyChoices. MyChoice 속성 XmlChoiceIdentifierAttribute 에서 멤버 값을 검색하는 열거형을 가져오거나 설정하는 다른 클래스 멤버를 지정 MemberName 하는 각 필드에 적용됩니다. 필드에 MyChoice 해당 열거형 멤버 EnumType 가 있는 단일 값으로 필드를 설정할 수 있습니다. ManyChoices 필드는 개체 배열을 반환합니다. ChoiceArray 필드는 열거형 값의 배열을 반환합니다. 필드의 각 배열 멤버에 ManyChoices 대해 해당 멤버는 필드에서 반환된 배열에서 찾을 수 ChoiceArray 있습니다.

#using <System.dll>
#using <System.xml.dll>

using namespace System;
using namespace System::Xml;
using namespace System::Xml::Serialization;
using namespace System::IO;

[XmlType(IncludeInSchema=false)]

public enum class ItemChoiceType
{
   None, Word, Number, DecimalNumber
};

public enum class MoreChoices
{
   None, Item, Amount, Temp
};

public ref class Choices
{
public:

   // The MyChoice field can be set to any one of 
   // the types below. 

   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word",String::typeid)]
   [XmlElement("Number",Int32::typeid)]
   [XmlElement("DecimalNumber",Double::typeid)]
   Object^ MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.

   [XmlIgnore]
   ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.

   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item",String::typeid)]
   [XmlElement("Amount",Int32::typeid)]
   [XmlElement("Temp",Double::typeid)]
   array<Object^>^ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.

   [XmlIgnore]
   array<MoreChoices>^ChoiceArray;
};

void SerializeObject( String^ filename );
void DeserializeObject( String^ filename );
int main()
{
   SerializeObject( "Choices.xml" );
   DeserializeObject( "Choices.xml" );
}

void SerializeObject( String^ filename )
{
   XmlSerializer^ mySerializer = gcnew XmlSerializer( Choices::typeid );
   TextWriter^ writer = gcnew StreamWriter( filename );
   Choices^ myChoices = gcnew Choices;

   // Set the MyChoice field to a string. Set the
   // EnumType to Word.
   myChoices->MyChoice = "Book";
   myChoices->EnumType = ItemChoiceType::Word;

   // Populate an object array with three items, one
   // of each enumeration type. Set the array to the 
   // ManyChoices field.
   array<Object^>^strChoices = {"Food",5,98.6};
   myChoices->ManyChoices = strChoices;

   // For each item in the ManyChoices array, add an
   // enumeration value.
   array<MoreChoices>^ itmChoices = {MoreChoices::Item,MoreChoices::Amount,MoreChoices::Temp};
   myChoices->ChoiceArray = itmChoices;
   mySerializer->Serialize( writer, myChoices );
   writer->Close();
}

void DeserializeObject( String^ filename )
{
   XmlSerializer^ ser = gcnew XmlSerializer( Choices::typeid );

   // A FileStream is needed to read the XML document.
   FileStream^ fs = gcnew FileStream( filename,FileMode::Open );
   Choices^ myChoices = safe_cast<Choices^>(ser->Deserialize( fs ));
   fs->Close();

   // Disambiguate the MyChoice value using the enumeration.
   if ( myChoices->EnumType == ItemChoiceType::Word )
   {
      Console::WriteLine( "Word: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::Number )
   {
      Console::WriteLine( "Number: {0}", myChoices->MyChoice->ToString() );
   }
   else
   if ( myChoices->EnumType == ItemChoiceType::DecimalNumber )
   {
      Console::WriteLine( "DecimalNumber: {0}", myChoices->MyChoice->ToString() );
   }

   // Disambiguate the ManyChoices values using the enumerations.
   for ( int i = 0; i < myChoices->ManyChoices->Length; i++ )
   {
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Item )
            Console::WriteLine( "Item: {0}", myChoices->ManyChoices[ i ] );
      else
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Amount )
            Console::WriteLine( "Amount: ", myChoices->ManyChoices[ i ]->ToString() );
      if ( myChoices->ChoiceArray[ i ] == MoreChoices::Temp )
            Console::WriteLine( "Temp: {0}", myChoices->ManyChoices[ i ]->ToString() );
   }
}

using System;
using System.Xml;
using System.Xml.Serialization;
using System.IO;

public class Choices{
   // The MyChoice field can be set to any one of 
   // the types below. 
   [XmlChoiceIdentifier("EnumType")]
   [XmlElement("Word", typeof(string))]
   [XmlElement("Number", typeof(int))]
   [XmlElement("DecimalNumber", typeof(double))]
   public object MyChoice;

   // Don't serialize this field. The EnumType field
   // contains the enumeration value that corresponds
   // to the MyChoice field value.
   [XmlIgnore]
   public ItemChoiceType EnumType;

   // The ManyChoices field can contain an array
   // of choices. Each choice must be matched to
   // an array item in the ChoiceArray field.
   [XmlChoiceIdentifier("ChoiceArray")]
   [XmlElement("Item", typeof(string))]
   [XmlElement("Amount", typeof(int))]
   [XmlElement("Temp", typeof(double))]
   public object[] ManyChoices;

   // TheChoiceArray field contains the enumeration
   // values, one for each item in the ManyChoices array.
   [XmlIgnore]
   public MoreChoices[] ChoiceArray;
}

[XmlType(IncludeInSchema=false)]
public enum ItemChoiceType{
   None,
   Word, 
   Number,
   DecimalNumber
}

public enum MoreChoices{
   None,
   Item,
   Amount,
   Temp
}

public class Test{
   static void Main(){
      Test t = new Test();
      t.SerializeObject("Choices.xml");
      t.DeserializeObject("Choices.xml");
   }

   private void SerializeObject(string filename){
      XmlSerializer mySerializer = 
      new XmlSerializer(typeof(Choices));
      TextWriter writer = new StreamWriter(filename);
      Choices myChoices = new Choices();

      // Set the MyChoice field to a string. Set the
      // EnumType to Word.
      myChoices.MyChoice= "Book";
      myChoices.EnumType = ItemChoiceType.Word;

      // Populate an object array with three items, one
      // of each enumeration type. Set the array to the 
      // ManyChoices field.
      object[] strChoices = new object[]{"Food",  5, 98.6};
      myChoices.ManyChoices=strChoices;

      // For each item in the ManyChoices array, add an
      // enumeration value.
      MoreChoices[] itmChoices = new MoreChoices[]
      {MoreChoices.Item, 
      MoreChoices.Amount,
      MoreChoices.Temp};
      myChoices.ChoiceArray=itmChoices;
      
      mySerializer.Serialize(writer, myChoices);
      writer.Close();
   }

   private void DeserializeObject(string filename){
      XmlSerializer ser = new XmlSerializer(typeof(Choices));

      // A FileStream is needed to read the XML document.
      FileStream fs = new FileStream(filename, FileMode.Open);
      Choices myChoices = (Choices)
      ser.Deserialize(fs);
      fs.Close();

      // Disambiguate the MyChoice value using the enumeration.
      if(myChoices.EnumType == ItemChoiceType.Word){
           Console.WriteLine("Word: " +  
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.Number){
           Console.WriteLine("Number: " +
            myChoices.MyChoice.ToString());
        }
      else if(myChoices.EnumType == ItemChoiceType.DecimalNumber){
           Console.WriteLine("DecimalNumber: " +
            myChoices.MyChoice.ToString());
        }

      // Disambiguate the ManyChoices values using the enumerations.
      for(int i = 0; i<myChoices.ManyChoices.Length; i++){
      if(myChoices.ChoiceArray[i] == MoreChoices.Item)
        Console.WriteLine("Item: " + (string) myChoices.ManyChoices[i]);
      else if(myChoices.ChoiceArray[i] == MoreChoices.Amount)
        Console.WriteLine("Amount: " + myChoices.ManyChoices[i].ToString());
      if(myChoices.ChoiceArray[i] == MoreChoices.Temp)
        Console.WriteLine("Temp: " + (string) myChoices.ManyChoices[i].ToString());
        }
   }
}

Imports System.Xml
Imports System.Xml.Serialization
Imports System.IO

Public Class Choices
   ' The MyChoice field can be set to any one of 
   ' the types below. 
   <XmlChoiceIdentifier("EnumType"), _
   XmlElement("Word", GetType(String)), _
   XmlElement("Number", GetType(Integer)), _
   XmlElement("DecimalNumber", GetType(double))> _
   Public MyChoice As Object 

   ' Don't serialize this field. The EnumType field
   ' contains the enumeration value that corresponds
   ' to the MyChoice field value.
   <XmlIgnore> _
   Public EnumType As ItemChoiceType 

   'The ManyChoices field can contain an array
   ' of choices. Each choice must be matched to
   ' an array item in the ChoiceArray field.
   <XmlChoiceIdentifier("ChoiceArray"), _
   XmlElement("Item", GetType(string)), _
   XmlElement("Amount", GetType(Integer)), _
   XmlElement("Temp", GetType(double))> _
   Public ManyChoices() As Object

   ' TheChoiceArray field contains the enumeration
   ' values, one for each item in the ManyChoices array.
   <XmlIgnore> _
   Public ChoiceArray() As MoreChoices
End Class

<XmlType(IncludeInSchema:=false)> _
Public Enum ItemChoiceType
   None
   Word 
   Number
   DecimalNumber
End Enum

<XmlType(IncludeInSchema:=false)> _
Public Enum MoreChoices
   None
   Item
   Amount
   Temp
End Enum

Public Class Test
   Shared Sub Main()
      Dim t  As Test = New Test()
      t.SerializeObject("Choices.xml")
      t.DeserializeObject("Choices.xml")
   End Sub

   private Sub SerializeObject(filename As string)
      Dim mySerializer As XmlSerializer = _
      New XmlSerializer(GetType(Choices))
      Dim writer As TextWriter = New StreamWriter(filename)
      Dim myChoices As Choices = New Choices()

      ' Set the MyChoice field to a string. Set the
      ' EnumType to Word.
      myChoices.MyChoice= "Book"
      myChoices.EnumType = ItemChoiceType.Word

      ' Populate an object array with three items, one
      ' of each enumeration type. Set the array to the 
      ' ManyChoices field.
      Dim strChoices () As Object = New object(){"Food",  5, 98.6}
      myChoices.ManyChoices=strChoices

      ' For each item in the ManyChoices array, add an
      ' enumeration value.
      Dim itmChoices () As MoreChoices = New MoreChoices() _
      {MoreChoices.Item, _
      MoreChoices.Amount, _
      MoreChoices.Temp}
      myChoices.ChoiceArray=itmChoices
      
      mySerializer.Serialize(writer, myChoices)
      writer.Close()
   End Sub

   private Sub DeserializeObject(filename As string)
      Dim ser As XmlSerializer = New XmlSerializer(GetType(Choices))
      

      ' A FileStream is needed to read the XML document.
      Dim fs As FileStream = New FileStream(filename, FileMode.Open)
      
      Dim myChoices As Choices = CType(ser.Deserialize(fs), Choices)

      fs.Close()

      ' Disambiguate the MyChoice value Imports the enumeration.
      if myChoices.EnumType = ItemChoiceType.Word Then
           Console.WriteLine("Word: " & _
           myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.Number Then 
           Console.WriteLine("Number: " & _
            myChoices.MyChoice.ToString())
        
      else if myChoices.EnumType = ItemChoiceType.DecimalNumber Then
         Console.WriteLine("DecimalNumber: " & _
            myChoices.MyChoice.ToString())
        End If

      ' Disambiguate the ManyChoices values Imports the enumerations.
      Dim i As Integer
      for i = 0 to myChoices.ManyChoices.Length -1
      if myChoices.ChoiceArray(i) = MoreChoices.Item Then
        Console.WriteLine("Item: " +  _
        myChoices.ManyChoices(i).ToString())
      else if myChoices.ChoiceArray(i) = MoreChoices.Amount Then
        Console.WriteLine("Amount: " + _
        myChoices.ManyChoices(i).ToString())
      else if (myChoices.ChoiceArray(i) = MoreChoices.Temp)
        Console.WriteLine("Temp: " + _
        myChoices.ManyChoices(i).ToString())
        End If
        Next i
      
   End Sub
End Class

설명

값에 명명된 필드가 반환하는 열거형에 하나 이상의 멤버가 MemberName 있어야 합니다. 기본적으로 해당 열거형 이름은 적용되는 필드 XmlChoiceIdentifierAttribute 의 이름을 사용합니다.

적용 대상

다음을 통해 공유

XmlChoiceIdentifierAttribute.MemberName 속성

정의

속성 값

예제

설명

적용 대상

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