Nata
Norint pasiekti šį puslapį, reikalingas leidimas. Galite pabandyti prisijungti arba pakeisti katalogus.
Norint pasiekti šį puslapį, reikalingas leidimas. Galite pabandyti pakeisti katalogus.
type 'type' does not have an overloaded member 'operator ->'
Remarks
You need to define operator->() to use this pointer operation.
Examples
The following example generates C2819:
// C2819.cpp
// compile with: /c
class A {
public:
int i;
};
class B {};
void C(B j) {
j->i; // C2819
}
class D {
A* pA;
public:
A* operator->() {
return pA;
}
};
void F(D j) {
j->i;
}
C2819 can also occur when using C++ Stack Semantics for Reference Types. The following example generates C2819:
// C2819_b.cpp
// compile with: /clr
ref struct R {
void Test() {}
};
int main() {
R r;
r->Test(); // C2819
r.Test(); // OK
}