Walkthrough: Creating and Implementing Interfaces (Visual Basic)
Interfaces describe the characteristics of properties, methods, and events, but leave the implementation details up to structures or classes.
This walkthrough demonstrates how to declare and implement an interface.
Note
This walkthrough doesn't provide information about how to create a user interface.
Note
Your computer might show different names or locations for some of the Visual Studio user interface elements in the following instructions. The Visual Studio edition that you have and the settings that you use determine these elements. For more information, see Personalizing the IDE.
To define an interface
Open a new Visual Basic Windows Application project.
Add a new module to the project by clicking Add Module on the Project menu.
Name the new module
Module1.vb
and click Add. The code for the new module is displayed.Define an interface named
TestInterface
withinModule1
by typingInterface TestInterface
between theModule
andEnd Module
statements, and then pressing ENTER. The Code Editor indents theInterface
keyword and adds anEnd Interface
statement to form a code block.Define a property, method, and event for the interface by placing the following code between the
Interface
andEnd Interface
statements:Property Prop1() As Integer Sub Method1(ByVal X As Integer) Event Event1()
Implementation
You may notice that the syntax used to declare interface members is different from the syntax used to declare class members. This difference reflects the fact that interfaces cannot contain implementation code.
To implement the interface
Add a class named
ImplementationClass
by adding the following statement toModule1
, after theEnd Interface
statement but before theEnd Module
statement, and then pressing ENTER:Class ImplementationClass
If you are working within the integrated development environment, the Code Editor supplies a matching
End Class
statement when you press ENTER.Add the following
Implements
statement toImplementationClass
, which names the interface the class implements:Implements TestInterface
When listed separately from other items at the top of a class or structure, the
Implements
statement indicates that the class or structure implements an interface.If you are working within the integrated development environment, the Code Editor implements the class members required by
TestInterface
when you press ENTER, and you can skip the next step.If you are not working within the integrated development environment, you must implement all the members of the interface
MyInterface
. Add the following code toImplementationClass
to implementEvent1
,Method1
, andProp1
:Event Event1() Implements TestInterface.Event1 Public Sub Method1(ByVal X As Integer) Implements TestInterface.Method1 End Sub Public Property Prop1() As Integer Implements TestInterface.Prop1 Get End Get Set(ByVal value As Integer) End Set End Property
The
Implements
statement names the interface and interface member being implemented.Complete the definition of
Prop1
by adding a private field to the class that stored the property value:' Holds the value of the property. Private pval As Integer
Return the value of the
pval
from the property get accessor.Return pval
Set the value of
pval
in the property set accessor.pval = value
Complete the definition of
Method1
by adding the following code.MsgBox("The X parameter for Method1 is " & X) RaiseEvent Event1()
To test the implementation of the interface
Right-click the startup form for your project in the Solution Explorer, and click View Code. The editor displays the class for your startup form. By default, the startup form is called
Form1
.Add the following
testInstance
field to theForm1
class:Dim WithEvents testInstance As TestInterface
By declaring
testInstance
asWithEvents
, theForm1
class can handle its events.Add the following event handler to the
Form1
class to handle events raised bytestInstance
:Sub EventHandler() Handles testInstance.Event1 MsgBox("The event handler caught the event.") End Sub
Add a subroutine named
Test
to theForm1
class to test the implementation class:Sub Test() ' Create an instance of the class. Dim T As New ImplementationClass ' Assign the class instance to the interface. ' Calls to the interface members are ' executed through the class instance. testInstance = T ' Set a property. testInstance.Prop1 = 9 ' Read the property. MsgBox("Prop1 was set to " & testInstance.Prop1) ' Test the method and raise an event. testInstance.Method1(5) End Sub
The
Test
procedure creates an instance of the class that implementsMyInterface
, assigns that instance to thetestInstance
field, sets a property, and runs a method through the interface.Add code to call the
Test
procedure from theForm1 Load
procedure of your startup form:Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Test() ' Test the class. End Sub
Run the
Test
procedure by pressing F5. The message "Prop1 was set to 9" is displayed. After you click OK, the message "The X parameter for Method1 is 5" is displayed. Click OK, and the message "The event handler caught the event" is displayed.