Double.MaxValue Veld

Definitie

Naamruimte:

System

Assembly:

mscorlib.dll

Vertegenwoordigt de grootst mogelijke waarde van een Double. Dit veld is constant.

public: double MaxValue = 1.7976931348623157E+308;

public const double MaxValue = 1.7976931348623157E+308;

val mutable MaxValue : double

Public Const MaxValue As Double  = 1.7976931348623157E+308

Waarde van veld

Value = 1.7976931348623157E+308

Double

Voorbeelden

Het volgende codevoorbeeld illustreert het gebruik van Double.MaxValue:

public class Temperature {
    public static double MinValue {
        get {
            return Double.MinValue;
        }
    }

    public static double MaxValue {
        get {
            return Double.MaxValue;
        }
    }

    // The value holder
    protected double m_value;

    public double Value {
        get {
            return m_value;
        }
        set {
            m_value = value;
        }
    }

    public double Celsius {
        get {
            return (m_value-32.0)/1.8;
        }
        set {
            m_value = 1.8*value+32.0;
        }
    }
}

type Temperature() =
    static member MinValue =
        Double.MinValue

    static member MaxValue =
        Double.MaxValue

    member val Value = 0. with get, set

    member this.Celsius
        with get () =
            (this.Value - 32.) / 1.8
        and set (value) =
            this.Value <- 1.8 * value + 32.

Public Class Temperature

    Public Shared ReadOnly Property MinValue() As Double
        Get
            Return Double.MinValue
        End Get
    End Property

    Public Shared ReadOnly Property MaxValue() As Double
        Get
            Return Double.MaxValue
        End Get
    End Property

    ' The value holder
    Protected m_value As Double

    Public Property Value() As Double
        Get
            Return m_value
        End Get
        Set(ByVal Value As Double)
            m_value = Value
        End Set
    End Property

    Public Property Celsius() As Double
        Get
            Return (m_value - 32) / 1.8
        End Get
        Set(ByVal Value As Double)
            m_value = Value * 1.8 + 32
        End Set
    End Property
End Class

Opmerkingen

De waarde van deze constante is positief 1,7976931348623157E+308.

Het resultaat van een bewerking die groter is Double.MaxValue dan is Double.PositiveInfinity. In het volgende voorbeeld Double.PositiveInfinity worden toevoegings-, vermenigvuldigings- en exponentiëringsbewerkingen uitgevoerd wanneer het resultaat groter is Double.MaxValue.

using System;

public class Example
{
   public static void Main()
   {
      double result1 = 7.997e307 + 9.985e307;
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result1, Double.IsPositiveInfinity(result1));

      double result2 = 1.5935e250 * 7.948e110;
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result2, Double.IsPositiveInfinity(result2));

      double result3 = Math.Pow(1.256e100, 1.34e20);
      Console.WriteLine("{0} (Positive Infinity: {1})",
                        result3, Double.IsPositiveInfinity(result3));
   }
}
// The example displays the following output:
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)

open System

let result1 = 7.997e307 + 9.985e307
printfn $"{result1} (Positive Infinity: {Double.IsPositiveInfinity result1})"

let result2 = 1.5935e250 * 7.948e110
printfn $"{result2} (Positive Infinity: {Double.IsPositiveInfinity result2})"

let result3 = Math.Pow(1.256e100, 1.34e20)
printfn $"{result3} (Positive Infinity: {Double.IsPositiveInfinity result3})"
// The example displays the following output:
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)
//    Infinity (Positive Infinity: True)

Module Example
   Public Sub Main()
      Dim result1 As Double = 7.997e307 + 9.985e307
      Console.WriteLine("{0} (Positive Infinity: {1})", 
                        result1, Double.IsPositiveInfinity(result1))
      
      Dim result2 As Double = 1.5935e250 * 7.948e110
      Console.WriteLine("{0} (Positive Infinity: {1})", 
                        result2, Double.IsPositiveInfinity(result2))
      
      Dim result3 As Double = Math.Pow(1.256e100, 1.34e20)
      Console.WriteLine("{0} (Positive Infinity: {1})", 
                        result3, Double.IsPositiveInfinity(result3))
   End Sub
End Module
' The example displays the following output:
'    Infinity (Positive Infinity: True)
'    Infinity (Positive Infinity: True)
'    Infinity (Positive Infinity: True)