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SAXSource.InputSource Property

Definition

Get the SAX InputSource to be used for the Source. -or- Set the SAX InputSource to be used for the Source.

public virtual Org.Xml.Sax.InputSource? InputSource { [Android.Runtime.Register("getInputSource", "()Lorg/xml/sax/InputSource;", "GetGetInputSourceHandler")] get; [Android.Runtime.Register("setInputSource", "(Lorg/xml/sax/InputSource;)V", "GetSetInputSource_Lorg_xml_sax_InputSource_Handler")] set; }
[<get: Android.Runtime.Register("getInputSource", "()Lorg/xml/sax/InputSource;", "GetGetInputSourceHandler")>]
[<set: Android.Runtime.Register("setInputSource", "(Lorg/xml/sax/InputSource;)V", "GetSetInputSource_Lorg_xml_sax_InputSource_Handler")>]
member this.InputSource : Org.Xml.Sax.InputSource with get, set

Property Value

A valid InputSource reference, or null.

Attributes

Remarks

Property getter documentation:

Get the SAX InputSource to be used for the Source.

Java documentation for javax.xml.transform.sax.SAXSource.getInputSource().

Property setter documentation:

Set the SAX InputSource to be used for the Source.

Java documentation for javax.xml.transform.sax.SAXSource.setInputSource(org.xml.sax.InputSource).

Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.

Applies to