iscntrl

Testa se um elemento em uma localidade é um caractere de controle.

template<Class CharType> 
   bool iscntrl( 
      CharType _Ch,  
      const locale& _Loc 
   )

Parâmetros

• _Ch
  O elemento a ser testado.

• _Loc
  A localidade que contém o elemento a ser testado.

Valor de retorno

true se o elemento testado for um caractere de controle; false se não for.

Comentários

A função do modelo retorna use_facet<C<CharType> >(_Loc).é(::<cntrl>, _ChdectypeCharType).

Exemplo

// locale_iscntrl.cpp
// compile with: /EHsc
#include <locale>
#include <iostream>

using namespace std;

int main( )   
{
   locale loc ( "German_Germany" );
   bool result1 = iscntrl ( 'L', loc );
   bool result2 = iscntrl ( '\n', loc );
   bool result3 = iscntrl ( '\t', loc );

   if ( result1 )
      cout << "The character 'L' in the locale is "
           << "a control character." << endl;
   else
      cout << "The character 'L' in the locale is "
           << " not a control character." << endl;

   if ( result2 )
      cout << "The character-set 'backslash-n' in the locale\n is "
           << "a control character." << endl;
   else
      cout << "The character-set 'backslash-n' in the locale\n is "
           << " not a control character." << endl;

   if ( result3 )
      cout << "The character-set 'backslash-t' in the locale\n is "
           << "a control character." << endl;
   else
      cout << "The character-set 'backslash-n' in the locale \n is "
           << " not a control character." << endl;
}

Saída

The character 'L' in the locale is  not a control character.
The character-set 'backslash-n' in the locale
 is a control character.
The character-set 'backslash-t' in the locale
 is a control character.

Requisitos

localidade <deCabeçalho: >

Namespace: std