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Método UserDefinedTableType (String)

Returns an object that represents the specified type.

Namespace:  Microsoft.SqlServer.Management.Smo
Assembly:  Microsoft.SqlServer.Smo (em Microsoft.SqlServer.Smo.dll)

Sintaxe

'Declaração
Public Shared Function UserDefinedTableType ( _
    type As String _
) As DataType
'Uso
Dim type As String
Dim returnValue As DataType

returnValue = DataType.UserDefinedTableType(type)

public static DataType UserDefinedTableType(
    string type
)

public:
static DataType^ UserDefinedTableType(
    String^ type
)

static member UserDefinedTableType : 
        type:string -> DataType 

public static function UserDefinedTableType(
    type : String
) : DataType

Parâmetros

Valor de retorno

Tipo: Microsoft.SqlServer.Management.Smo. . :: . .DataType
A DataType object value.

Exemplos

The following code example shows how to create a user-defined table type.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];
Schema schema1 = new Schema(db, "ExampleSchema");
schema1.Create();
UserDefinedTableType udtt = new UserDefinedTableType(db, "udtt", "ExampleSchema");
Column c = new Column(udtt, "Column 1", DataType.Int);
udtt.Columns.Add(c);
udtt.Create();
DataType userTable = new DataType(SqlDataType.UserDefinedTableType, "udtt");
userTable.Schema = "ExampleSchema";

Powershell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = $srv.Databases.Item("AdventureWorks2008R2")
$schema1 = new-object Microsoft.SqlServer.Management.Smo.Schema($db, "ExampleSchema")
$schema1.Create()
$udtt = new-object Microsoft.SqlServer.Management.Smo.UserDefinedTableType($db, "udtt", "ExampleSchema")
$c = new-object Microsoft.SqlServer.Management.Smo.Column($udtt, "Column 1", [Microsoft.SqlServer.Management.Smo.DataType]::Int)
$udtt.Columns.Add($c)
$udtt.Create()
$userTable = new-object Microsoft.SqlServer.Management.Smo.DataType([Microsoft.SqlServer.Management.Smo.SqlDataType]::UserDefinedTableType, "udtt")
$userTable.Schema = "ExampleSchema"