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Enumerable.Max Method (IEnumerable<Int32>)

Microsoft Silverlight will reach end of support after October 2021. Learn more.

Returns the maximum value in a sequence of Int32 values.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

Syntax

'Declaration
<ExtensionAttribute> _
Public Shared Function Max ( _
    source As IEnumerable(Of Integer) _
) As Integer

public static int Max(
    this IEnumerable<int> source
)

Parameters

Return Value

Type: System.Int32
The maximum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Int32>. When you use instance method syntax to call this method, omit the first parameter.

Exceptions

Exception Condition
ArgumentNullException

source is nulla null reference (Nothing in Visual Basic).
InvalidOperationException

source contains no elements.

Remarks

The Max(IEnumerable<Int32>) method uses the Int32 implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Max() clause translates to an invocation of Max.

Examples

The following code example demonstrates how to use Max(IEnumerable<Int64>) to determine the maximum value in a sequence.

NoteNote:

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

 
      ' Create a list of Long values.
      Dim longs As New List(Of Long)(New Long() _
                                     {4294967296L, 466855135L, 81125L})

      ' Get the maximum value in the list.
      Dim max As Long = longs.Max()

      ' Display the result.
      outputBlock.Text &= "The largest number is " & max & vbCrLf

      ' This code produces the following output:
      '
      ' The largest number is 4294967296


      List<long> longs = new List<long> { 4294967296L, 466855135L, 81125L };

      long max = longs.Max();

      outputBlock.Text += String.Format("The largest number is {0}.", max) + "\n";

      /*
       This code produces the following output:

       The largest number is 4294967296.
      */

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.