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OutArgument<T>.FromExpression(Activity<Location<T>>) Método

  • Referência

Definição

Namespace:
System.Activities
Assembly:
System.Activities.dll

Inicializa e retorna um novo OutArgument<T> construído usando o Activity<TResult> especificado.

public:
 static System::Activities::OutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.OutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.OutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As OutArgument(Of T)

Parâmetros

expression
Activity<Location<T>>

O valor do argumento.

Retornos

OutArgument<T>

O novo argumento.

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