DateTimeOffset.Day Property

Definition

Gets the day of the month represented by the current DateTimeOffset object.

public int Day { get; }

Property Value

The day component of the current DateTimeOffset object, expressed as a value between 1 and 31.

Examples

The following example displays the day component of a DateTimeOffset object in three different ways:

  • By retrieving the value of the Day property.

  • By calling the ToString(String) method with the "d" format specifier.

  • By calling the ToString(String) method with the "dd" format specifier.

DateTimeOffset theTime = new DateTimeOffset(2007, 5, 1, 16, 35, 0,
                                            DateTimeOffset.Now.Offset);
Console.WriteLine("The day component of {0} is {1}.",
                  theTime, theTime.Day);

Console.WriteLine("The day component of {0} is{1}.",
                  theTime, theTime.ToString(" d"));

Console.WriteLine("The day component of {0} is {1}.",
                  theTime, theTime.ToString("dd"));
// The example produces the following output:
//    The day component of 5/1/2007 4:35:00 PM -08:00 is 1.
//    The day component of 5/1/2007 4:35:00 PM -08:00 is 1.
//    The day component of 5/1/2007 4:35:00 PM -08:00 is 01.

Remarks

The Day property is not affected by the value of the Offset property.

You can also create a string representation of a DateTimeOffset object's day component by calling the ToString method with the "d" or "dd" custom format specifiers.

Applies to

Produs Versiuni
.NET Core 1.0, Core 1.1, Core 2.0, Core 2.1, Core 2.2, Core 3.0, Core 3.1, 5, 6, 7, 8, 9
.NET Framework 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
.NET Standard 1.0, 1.1, 1.2, 1.3, 1.4, 1.5, 1.6, 2.0, 2.1
UWP 10.0