Vector<T>.BitwiseAnd(Vector<T>, Vector<T>) Operator
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Returns a new vector by performing a bitwise And
operation on each of the elements in two vectors.
public:
static System::Numerics::Vector<T> operator &(System::Numerics::Vector<T> left, System::Numerics::Vector<T> right);
public static System.Numerics.Vector<T> operator & (System.Numerics.Vector<T> left, System.Numerics.Vector<T> right);
static member ( &&& ) : System.Numerics.Vector<'T (requires 'T : struct)> * System.Numerics.Vector<'T (requires 'T : struct)> -> System.Numerics.Vector<'T (requires 'T : struct)>
static member ( &&& ) : System.Numerics.Vector<'T> * System.Numerics.Vector<'T> -> System.Numerics.Vector<'T>
Public Shared Operator And (left As Vector(Of T), right As Vector(Of T)) As Vector(Of T)
Parameters
- left
- Vector<T>
The first vector.
- right
- Vector<T>
The second vector.
Returns
The vector that results from the bitwise And
of left
and right
.
Exceptions
.NET 5 and later: Type T
is not supported.
Remarks
The BitwiseAnd method defines the bitwise And
operation for Vector<T> objects.
Applies to
Colaborați cu noi pe GitHub
Sursa pentru acest conținut poate fi găsită pe GitHub, unde puteți, de asemenea, să creați și să consultați probleme și solicitări de tragere. Pentru mai multe informații, consultați ghidul nostru pentru colaboratori.