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User-defined explicit and implicit conversion operators

  • Članak

A user-defined type can define a custom implicit or explicit conversion from or to another type. Implicit conversions don't require special syntax to be invoked and can occur in various situations, for example, in assignments and methods invocations. Predefined C# implicit conversions always succeed and never throw an exception. User-defined implicit conversions should behave in that way as well. If a custom conversion can throw an exception or lose information, define it as an explicit conversion.

User-defined conversions aren't considered by the is and as operators. Use a cast expression to invoke a user-defined explicit conversion.

Use the operator and implicit or explicit keywords to define an implicit or explicit conversion, respectively. The type that defines a conversion must be either a source type or a target type of that conversion. A conversion between two user-defined types can be defined in either of the two types.

The following example demonstrates how to define an implicit and explicit conversion:

using System;

public readonly struct Digit
{
    private readonly byte digit;

    public Digit(byte digit)
    {
        if (digit > 9)
        {
            throw new ArgumentOutOfRangeException(nameof(digit), "Digit cannot be greater than nine.");
        }
        this.digit = digit;
    }

    public static implicit operator byte(Digit d) => d.digit;
    public static explicit operator Digit(byte b) => new Digit(b);

    public override string ToString() => $"{digit}";
}

public static class UserDefinedConversions
{
    public static void Main()
    {
        var d = new Digit(7);

        byte number = d;
        Console.WriteLine(number);  // output: 7

        Digit digit = (Digit)number;
        Console.WriteLine(digit);  // output: 7
    }
}

Beginning with C# 11, you can define checked explicit conversion operators. For more information, see the User-defined checked operators section of the Arithmetic operators article.

You also use the operator keyword to overload a predefined C# operator. For more information, see Operator overloading.

C# language specification

For more information, see the following sections of the C# language specification:

See also