Type.GetElementType Metod

Definition

När det åsidosättas i en härledd klass returnerar Type det objekt som omfattas eller refereras till av den aktuella matrisen, pekaren eller referenstypen.

public:
 abstract Type ^ GetElementType();
public abstract Type GetElementType();
abstract member GetElementType : unit -> Type
Public MustOverride Function GetElementType () As Type

Returer

Objektets Type omslutna eller refererade till av den aktuella matrisen, pekaren eller referenstypen, eller null om den aktuella Type inte är en matris eller en pekare, eller inte skickas med referens, eller representerar en generisk typ eller en typparameter i definitionen av en allmän typ eller allmän metod.

Implementeringar

Exempel

I följande exempel visas hur du använder GetElementType metoden.

using System;
class TestGetElementType
{
    public static void Main()
    {
        int[] array = {1,2,3};
        Type t = array.GetType();
        Type t2 = t.GetElementType();
        Console.WriteLine("The element type of {0} is {1}.",array, t2.ToString());
        TestGetElementType newMe = new TestGetElementType();
        t = newMe.GetType();
        t2 = t.GetElementType();
        Console.WriteLine("The element type of {0} is {1}.", newMe, t2==null? "null" : t2.ToString());
    }
}

/* This code produces the following output:

The element type of System.Int32[] is System.Int32.
The element type of TestGetElementType is null.
 */
type TestGetElementType() = class end
do
    let array = [| 1; 2; 3 |]
    let t = array.GetType()
    let t2 = t.GetElementType()
    printfn $"The element type of {array} is {t2}."
    
    let newMe = TestGetElementType()
    let t = newMe.GetType()
    let t2 = t.GetElementType()
    printfn $"""The element type of {newMe} is {if t2 = null then "null" else string t2}."""

(* This code produces the following output:

The element type of System.Int32[] is System.Int32.
The element type of TestGetElementType is null.
 *)
Class TestGetElementType

    Public Shared Sub Main()
        Dim array As Integer() = {1, 2, 3}
        Dim t As Type = array.GetType()
        Dim t2 As Type = t.GetElementType()
        Console.WriteLine("The element type of {0} is {1}.", array, t2.ToString())
        Dim newMe As New TestGetElementType()
        t = newMe.GetType()
        t2 = t.GetElementType()
        If t2 Is Nothing Then
            Console.WriteLine("The element type of {0} is {1}.", newMe, "null")
        Else
            Console.WriteLine("The element type of {0} is {1}.", newMe, t2.ToString())
        End If
    End Sub
End Class

' This code produces the following output:
'
'The element type of System.Int32[] is System.Int32.
'The element type of TestGetElementType is null.

Kommentarer

Den här metoden returnerar null för Array klassen.

Gäller för

Se även