Sending a Message by Posting an XML Element
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When the posting URL is retrieved, a client application can send all other requests to the conference center by sending the corresponding request elements using an HTTPS POST.
Code Example
The following example uses HttpWebRequest and HttpWebResponse classes supported by the Microsoft .NET Framework.
public XmlDocument PostXmlMessageRequest(XmlDocument xmldoc)
{
// Upon entering, xmldoc = messageRequest
// Upon exit, xmlReply = messageReply;
ASCIIEncoding encoder = new ASCIIEncoding();
XmlDocument xmlReply = null ;
// Post the <messageRequest> element to the conference center;
HttpWebRequest myReq = (HttpWebRequest)WebRequest.Create(postingUrl);
myReq.Method = "POST";
myReq.ContentType = "application/x-www-form-urlencoded";
HttpWebResponse myResp = null;
try
{
// Write the XML message to the request stream and
// send it to the conference center
byte[] byteArray = encoder.GetBytes(xmldoc.OuterXml);
myReq.ContentLength = byteArray.Length;
Stream reqStream = myReq.GetRequestStream();
reqStream.Write(byteArray, 0, byteArray.Length);
reqStream.Close();
// Get the response from the conference center
myResp = (HttpWebResponse)myReq.GetResponse();
Stream respStream = myResp.GetResponseStream();
if (myResp.ContentType == "application/xml")
{
xmlReply = new XmlDocument();
xmlReply.Load(respStream);
}
}
catch (Exception e)
{
// Log the error or implement other error handling routines
Console.WriteLine("Error: {0}\nStack trace: {1}",
e.Message, e.StackTrace);
}
finally
{
if (myResp != null)
myResp.Close();
}
return xmlReply;
}
VBScript Code Example
set xmlpost = createobject("WinHttp.WinHttpRequest.5.1")
xmlpost.Open "POST", postingUrl, "false"
xmlpost.send(xmldoc)
wscript.echo xmlpost.responseXML.xml & vbcrlf