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Inconsistent accessibility: field type 'type' is less accessible than field 'field'
The type of a field cannot be less accessible than the field itself because all public constructs must return a publicly accessible object.
Example
The following sample generates CS0052:
// CS0052.cs
public class MyClass2
{
// The following line causes an error because the field, M, is declared
// as public, but the type, MyClass, is private. Therefore the type is
// less accessible than the field.
public MyClass M; // CS0052
private class MyClass
{
}
// One way to resolve the error is to change the accessibility of the type
// to public.
//public class MyClass
// Another solution is to change the accessibility of the field to private.
// private MyClass M;
}
public class MainClass
{
public static void Main()
{
}
}
See Also
Reference
Access Modifiers (C# Reference)
Accessibility Levels (C# Reference)
Change History
Date |
History |
Reason |
---|---|---|
July 2009 |
Added explanation to the example. |
Customer feedback. |