Financial.SLN(Double, Double, Double) Method
Definition
Important
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Returns a value specifying the straight-line depreciation of an asset for a single period.
public:
static double SLN(double Cost, double Salvage, double Life);
public static double SLN (double Cost, double Salvage, double Life);
static member SLN : double * double * double -> double
Public Function SLN (Cost As Double, Salvage As Double, Life As Double) As Double
Parameters
- Cost
- Double
Required. The initial cost of the asset.
- Salvage
- Double
Required. The value of the asset at the end of its useful life.
- Life
- Double
Required. The length of the useful life of the asset.
Returns
The straight-line depreciation of an asset for a single period.
Exceptions
Life
= 0.
Examples
This example uses the SLN
function to return the straight-line depreciation of an asset for a single period given the asset's initial cost (InitCost
), the salvage value at the end of the asset's useful life (SalvageVal
), and the total life of the asset in years (LifeTime
).
Dim InitCost, SalvageVal, LifeTime, DepYear As Double
Dim Fmt As String = "###,##0.00"
InitCost = CDbl(InputBox("What's the initial cost of the asset?"))
SalvageVal = CDbl(InputBox("Enter the asset's value at end of its life."))
LifeTime = CDbl(InputBox("What's the asset's useful life in years?"))
' Use the SLN function to calculate the deprecation per year.
Dim SlnDepr As Double = SLN(InitCost, SalvageVal, LifeTime)
Dim msg As String = "The depreciation per year: " & Format(SlnDepr, Fmt)
msg &= vbCrLf & "Year" & vbTab & "Linear" & vbTab & "Doubling" & vbCrLf
' Use the SYD and DDB functions to calculate the deprecation for each year.
For DepYear = 1 To LifeTime
msg &= DepYear & vbTab &
Format(SYD(InitCost, SalvageVal, LifeTime, DepYear), Fmt) & vbTab &
Format(DDB(InitCost, SalvageVal, LifeTime, DepYear), Fmt) & vbCrLf
Next
MsgBox(msg)
Remarks
The depreciation period must be expressed in the same unit as the Life
argument. All arguments must be positive numbers.