SqlInt16.Modulus(SqlInt16, SqlInt16) Method

Reference

Definition

Namespace:: System.Data.SqlTypes

Assembly:: System.Data.Common.dll

Assembly:: System.Data.SqlClient.dll

Assembly:: System.Data.dll

Assembly:: netstandard.dll

Source:: SQLInt16.cs

Source:: SQLInt16.cs

Source:: SQLInt16.cs

Important

Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.

Divides two SqlInt16 values and returns the remainder.

public:
 static System::Data::SqlTypes::SqlInt16 Modulus(System::Data::SqlTypes::SqlInt16 x, System::Data::SqlTypes::SqlInt16 y);

public static System.Data.SqlTypes.SqlInt16 Modulus (System.Data.SqlTypes.SqlInt16 x, System.Data.SqlTypes.SqlInt16 y);

static member Modulus : System.Data.SqlTypes.SqlInt16 * System.Data.SqlTypes.SqlInt16 -> System.Data.SqlTypes.SqlInt16

Public Shared Function Modulus (x As SqlInt16, y As SqlInt16) As SqlInt16

Parameters

x: SqlInt16

A SqlInt16 value.

y: SqlInt16

A SqlInt16 value.

Returns

SqlInt16

The remainder left after division is performed on x and y.

Remarks

If either instance of x or y is null, the value is null.

Applies to

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