XmlEntityReference.Name Property
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Gets the name of the node.
public:
virtual property System::String ^ Name { System::String ^ get(); };
public override string Name { get; }
member this.Name : string
Public Overrides ReadOnly Property Name As String
Property Value
The name of the entity referenced.
Examples
The following example displays information on the entity reference node.
#using <System.Xml.dll>
using namespace System;
using namespace System::IO;
using namespace System::Xml;
int main()
{
// Create the XmlDocument.
XmlDocument^ doc = gcnew XmlDocument;
doc->LoadXml( "<!DOCTYPE book [<!ENTITY h 'hardcover'>]>"
"<book genre='novel' ISBN='1-861001-57-5'>"
"<title>Pride And Prejudice</title>"
"<style>&h;</style>"
"</book>" );
// Display information on the entity reference node.
XmlEntityReference^ entref = dynamic_cast<XmlEntityReference^>(doc->DocumentElement->LastChild->FirstChild);
Console::WriteLine( "Name of the entity reference: {0}", entref->Name );
Console::WriteLine( "The entity replacement text: {0}", entref->InnerText );
}
using System;
using System.IO;
using System.Xml;
public class Sample
{
public static void Main()
{
// Create the XmlDocument.
XmlDocument doc = new XmlDocument();
doc.LoadXml("<!DOCTYPE book [<!ENTITY h 'hardcover'>]>" +
"<book genre='novel' ISBN='1-861001-57-5'>" +
"<title>Pride And Prejudice</title>" +
"<style>&h;</style>" +
"</book>");
// Display information on the entity reference node.
XmlEntityReference entref = (XmlEntityReference) doc.DocumentElement.LastChild.FirstChild;
Console.WriteLine("Name of the entity reference: {0}", entref.Name);
Console.WriteLine("The entity replacement text: {0}", entref.InnerText);
}
}
Option Explicit
Option Strict
Imports System.IO
Imports System.Xml
Public Class Sample
Public Shared Sub Main()
' Create the XmlDocument.
Dim doc As New XmlDocument()
doc.LoadXml("<!DOCTYPE book [<!ENTITY h 'hardcover'>]>" & _
"<book genre='novel' ISBN='1-861001-57-5'>" & _
"<title>Pride And Prejudice</title>" & _
"<style>&h;</style>" & _
"</book>")
' Display information on the entity reference node.
Dim entref As XmlEntityReference = CType(doc.DocumentElement.LastChild.FirstChild, XmlEntityReference)
Console.WriteLine("Name of the entity reference: {0}", entref.Name)
Console.WriteLine("The entity replacement text: {0}", entref.InnerText)
End Sub
End Class
Applies to
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