Context.SendBroadcastAsUser Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Overloads
SendBroadcastAsUser(Intent, UserHandle) |
Version of |
SendBroadcastAsUser(Intent, UserHandle, String) |
Version of |
SendBroadcastAsUser(Intent, UserHandle)
Version of #sendBroadcast(Intent)
that allows you to specify the
user the broadcast will be sent to.
[Android.Runtime.Register("sendBroadcastAsUser", "(Landroid/content/Intent;Landroid/os/UserHandle;)V", "GetSendBroadcastAsUser_Landroid_content_Intent_Landroid_os_UserHandle_Handler")]
[Android.Runtime.RequiresPermission("android.permission.INTERACT_ACROSS_USERS")]
public abstract void SendBroadcastAsUser (Android.Content.Intent? intent, Android.OS.UserHandle? user);
[<Android.Runtime.Register("sendBroadcastAsUser", "(Landroid/content/Intent;Landroid/os/UserHandle;)V", "GetSendBroadcastAsUser_Landroid_content_Intent_Landroid_os_UserHandle_Handler")>]
[<Android.Runtime.RequiresPermission("android.permission.INTERACT_ACROSS_USERS")>]
abstract member SendBroadcastAsUser : Android.Content.Intent * Android.OS.UserHandle -> unit
Parameters
- intent
- Intent
The intent to broadcast
- user
- UserHandle
UserHandle to send the intent to.
- Attributes
Remarks
Version of #sendBroadcast(Intent)
that allows you to specify the user the broadcast will be sent to. This is not available to applications that are not pre-installed on the system image.
Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.
See also
Applies to
SendBroadcastAsUser(Intent, UserHandle, String)
Version of #sendBroadcast(Intent, String)
that allows you to specify the
user the broadcast will be sent to.
[Android.Runtime.Register("sendBroadcastAsUser", "(Landroid/content/Intent;Landroid/os/UserHandle;Ljava/lang/String;)V", "GetSendBroadcastAsUser_Landroid_content_Intent_Landroid_os_UserHandle_Ljava_lang_String_Handler")]
[Android.Runtime.RequiresPermission("android.permission.INTERACT_ACROSS_USERS")]
public abstract void SendBroadcastAsUser (Android.Content.Intent? intent, Android.OS.UserHandle? user, string? receiverPermission);
[<Android.Runtime.Register("sendBroadcastAsUser", "(Landroid/content/Intent;Landroid/os/UserHandle;Ljava/lang/String;)V", "GetSendBroadcastAsUser_Landroid_content_Intent_Landroid_os_UserHandle_Ljava_lang_String_Handler")>]
[<Android.Runtime.RequiresPermission("android.permission.INTERACT_ACROSS_USERS")>]
abstract member SendBroadcastAsUser : Android.Content.Intent * Android.OS.UserHandle * string -> unit
Parameters
- intent
- Intent
The Intent to broadcast; all receivers matching this Intent will receive the broadcast.
- user
- UserHandle
UserHandle to send the intent to.
- receiverPermission
- String
(optional) String naming a permission that a receiver must hold in order to receive your broadcast. If null, no permission is required.
- Attributes
Remarks
Version of #sendBroadcast(Intent, String)
that allows you to specify the user the broadcast will be sent to. This is not available to applications that are not pre-installed on the system image.
Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.
See also
- <xref:Android.Content.Context.SendBroadcast(Android.Content.Intent%2c+System.String)>