Dns.GetHostName Method
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
Gets the host name of the local computer.
public:
static System::String ^ GetHostName();
public static string GetHostName ();
static member GetHostName : unit -> string
Public Shared Function GetHostName () As String
Returns
A string that contains the DNS host name of the local computer.
Exceptions
An error is encountered when resolving the local host name.
Examples
The following example uses the GetHostName method to obtain the host name of the local computer.
public:
void DisplayLocalHostName()
{
try
{
// Get the local computer host name.
String^ hostName = Dns::GetHostName();
Console::WriteLine( "Computer name : {0}", hostName );
}
catch ( SocketException^ e )
{
Console::WriteLine( "SocketException caught!!!" );
Console::WriteLine( "Source : {0}", e->Source );
Console::WriteLine( "Message : {0}", e->Message );
}
catch ( Exception^ e )
{
Console::WriteLine( "Exception caught!!!" );
Console::WriteLine( "Source : {0}", e->Source );
Console::WriteLine( "Message : {0}", e->Message );
}
}
public void DisplayLocalHostName()
{
try {
// Get the local computer host name.
String hostName = Dns.GetHostName();
Console.WriteLine("Computer name :" + hostName);
}
catch(SocketException e) {
Console.WriteLine("SocketException caught!!!");
Console.WriteLine("Source : " + e.Source);
Console.WriteLine("Message : " + e.Message);
}
catch(Exception e)
{
Console.WriteLine("Exception caught!!!");
Console.WriteLine("Source : " + e.Source);
Console.WriteLine("Message : " + e.Message);
}
}
Public Sub DisplayLocalHostName()
Try
' Get the local computer host name.
Dim hostName As [String] = Dns.GetHostName()
Console.WriteLine(("Computer name :" + hostName))
Catch e As SocketException
Console.WriteLine("SocketException caught!!!")
Console.WriteLine(("Source : " + e.Source))
Console.WriteLine(("Message : " + e.Message))
Catch e As Exception
Console.WriteLine("Exception caught!!!")
Console.WriteLine(("Source : " + e.Source))
Console.WriteLine(("Message : " + e.Message))
End Try
Applies to
Співпраця з нами на GitHub
Джерело цього вмісту можна знайти на GitHub, де також можна створювати й переглядати запитання та запити на внесення змін. Докладні відомості наведено в нашому посібнику для співавторів.