如何使用 Entity Framework 保存多对多关系

Hui Liu-MSFT 41,146 信誉分 Microsoft 供应商
2024-04-02T07:28:23.24+00:00

嗨,我在 Flight 和 Journey 之间有很多关系,所以我创建了一个中间表来创建关系:

概率

问题是,我有一个航班列表和一个旅程,那么我如何创建代码来制作程序集,以便在使用实体框架保存它之后?

创建模型和上下文,此代码似乎没问题:

//process to create the Flight with the Transport list

 var journey = new Journey()

{

                    JourneyOrigin = origin,

                    JourneyDestination = destination,

                    JourneyPrice = SumPrice

};


var response = new JourneyFlight()

{

                    Journey = journey,

                    Flight = flights[0]

};


            

Note:此问题总结整理于:How to save a many to many relationship with Entity Framework

Entity Framework Core
Entity Framework Core
实体框架数据访问技术的轻量型、可扩展、开源、跨平台版本。
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  1. Jiale Xue - MSFT 35,556 信誉分 Microsoft 供应商
    2024-04-02T07:51:16.16+00:00

    欢迎来到 Microsoft Q&A,如果要在 ef core 中保存多对多关系,建议先使用代码生成模型,并在 OnModelCreating 事件中定义一些关系。

    下面是一个可以参考的代码示例。

    模型和 Dbcontext:

    public class JourneyFlight
        {
            public int JourneyFlightId { get; set; }
    
            public int JourneyId { get; set; }
            public int FlightId { get; set; }
    
            public Journey? journey { get; set; }
    
            public Flight? flight { get; set; }
    
    
        }
    
        public class Journey
        {
            public int JourneyId { get; set; }
    
            public double JourneyPrice { get; set; }
    
            public ICollection<JourneyFlight>? journeyFlights { get; set; }
        }
        public class Flight
        {
            public int FlightId { get; set; }
            public double FlightPrice { get; set;}
    
            public int TransportId { get; set; }
            public Transport? transport { get; set; }
            public ICollection<JourneyFlight>? journeyFlights { get; set; }
        }
    
        public class Transport
        {
            public int TransportId { get; set; }
    
            public int TransportFlightNumber { get; set; }
    
            public ICollection<Flight>? flights;
        }
    
        public class MyContext:DbContext
        {
            public DbSet<JourneyFlight> journeyFlights { get; set; }
    
            public DbSet<Journey> journeys { get; set; }
    
            public DbSet<Flight> flights { get; set; }
    
            public DbSet<Transport> transports { get; set; }
    
            protected override void OnConfiguring(DbContextOptionsBuilder optionsBuilder)
            {
                optionsBuilder.UseSqlServer("connstr");
            }
            protected override void OnModelCreating(ModelBuilder modelBuilder)
            {
                modelBuilder.Entity<JourneyFlight>().HasKey(m => new { m.JourneyId, m.FlightId });
                modelBuilder.Entity<JourneyFlight>().HasOne(m => m.journey).WithMany(m => m.journeyFlights).HasForeignKey(m=>m.JourneyId);
                modelBuilder.Entity<JourneyFlight>().HasOne(m => m.flight).WithMany(m => m.journeyFlights).HasForeignKey(m=>m.FlightId);
                modelBuilder.Entity<Flight>().HasOne(m => m.transport).WithMany(m => m.flights).HasForeignKey(m => m.TransportId);
    
            }
        } 
    

    如何在main方法中添加数据:

    MyContext context=new MyContext();
               JourneyFlight journeyFlight1=new JourneyFlight();
                JourneyFlight journeyFlight2 = new JourneyFlight();
                var j1=new Journey();
                j1.JourneyPrice = 100;
                var j2=new Journey();
                j2.JourneyPrice = 200; 
                var f1=new Flight();
                f1.FlightPrice = 50;
                var f2=new Flight();    
                f2.FlightPrice = 70;
                journeyFlight1.journey = j1;
                journeyFlight1.flight = f1;
                journeyFlight2.journey = j2;
                journeyFlight2.flight = f2;
                Transport transport = new Transport();
                transport.flights = new List<Flight>
                {
                    f1,
                    f2
                };
                transport.TransportFlightNumber = 1001;
                context.journeyFlights.Add(journeyFlight1);
                context.journeyFlights.Add(journeyFlight2);
                context.transports.Add(transport);
                context.SaveChanges();
    
    

    根据我的测试,我可以在sql server中得到以下结果:

    用户图像

    希望我的代码示例能对您有所帮助。


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