OutArgument<T>.FromExpression(Activity<Location<T>>) 方法
重要
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初始化和返回使用指定的 OutArgument<T> 构造的新 Activity<TResult>。
public:
static System::Activities::OutArgument<T> ^ FromExpression(System::Activities::Activity<System::Activities::Location<T> ^> ^ expression);
public static System.Activities.OutArgument<T> FromExpression (System.Activities.Activity<System.Activities.Location<T>> expression);
static member FromExpression : System.Activities.Activity<System.Activities.Location<'T>> -> System.Activities.OutArgument<'T>
Public Shared Function FromExpression (expression As Activity(Of Location(Of T))) As OutArgument(Of T)
新自变量。