DateTime.MinValue 字段
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
表示 DateTime 的最小可能值。 此字段为只读。
public: static initonly DateTime MinValue;
public static readonly DateTime MinValue;
staticval mutable MinValue : DateTime
Public Shared ReadOnly MinValue As DateTime
字段值
示例
下面的示例通过向其构造函数传递表示Int64一个时钟周期数的值来实例化DateTime对象。 在调用构造函数之前,该示例确保此值大于或等于 DateTime.MinValue.Ticks
且小于或等于 DateTime.MaxValue.Ticks
。 否则,它将引发 ArgumentOutOfRangeException。
// Attempt to assign an out-of-range value to a DateTime constructor.
long numberOfTicks = Int64.MaxValue;
DateTime validDate;
// Validate the value.
if (numberOfTicks >= DateTime.MinValue.Ticks &&
numberOfTicks <= DateTime.MaxValue.Ticks)
validDate = new DateTime(numberOfTicks);
else if (numberOfTicks < DateTime.MinValue.Ticks)
Console.WriteLine("{0:N0} is less than {1:N0} ticks.",
numberOfTicks,
DateTime.MinValue.Ticks);
else
Console.WriteLine("{0:N0} is greater than {1:N0} ticks.",
numberOfTicks,
DateTime.MaxValue.Ticks);
// The example displays the following output:
// 9,223,372,036,854,775,807 is greater than 3,155,378,975,999,999,999 ticks.
// Attempt to assign an out-of-range value to a DateTime constructor.
let numberOfTicks = Int64.MaxValue
// Validate the value.
if numberOfTicks >= DateTime.MinValue.Ticks &&
numberOfTicks <= DateTime.MaxValue.Ticks then
let validDate = DateTime numberOfTicks
()
elif numberOfTicks < DateTime.MinValue.Ticks then
printfn $"{numberOfTicks:N0} is less than {DateTime.MinValue.Ticks:N0} ticks."
else
printfn $"{numberOfTicks:N0} is greater than {DateTime.MaxValue.Ticks:N0} ticks."
// The example displays the following output:
// 9,223,372,036,854,775,807 is greater than 3,155,378,975,999,999,999 ticks.
' Attempt to assign an out-of-range value to a DateTime constructor.
Dim numberOfTicks As Long = Int64.MaxValue
Dim validDate As Date
' Validate the value.
If numberOfTicks >= Date.MinValue.Ticks And _
numberOfTicks <= Date.MaxValue.Ticks Then
validDate = New Date(numberOfTicks)
ElseIf numberOfTicks < Date.MinValue.Ticks Then
Console.WriteLine("{0:N0} is less than {1:N0} ticks.",
numberOfTicks,
DateTime.MinValue.Ticks)
Else
Console.WriteLine("{0:N0} is greater than {1:N0} ticks.",
numberOfTicks,
DateTime.MaxValue.Ticks)
End If
' The example displays the following output:
' 9,223,372,036,854,775,807 is greater than 3,155,378,975,999,999,999 ticks.
注解
此常量的值相当于公历中的 00:00:00.0000000 UTC,0001 年 1 月 1 日。
MinValue 定义分配给未初始化 DateTime 变量的日期和时间。 下面的示例对此进行了演示。
// Define an uninitialized date.
DateTime date1 = new DateTime();
Console.Write(date1);
if (date1.Equals(DateTime.MinValue))
Console.WriteLine(" (Equals Date.MinValue)");
// The example displays the following output:
// 1/1/0001 12:00:00 AM (Equals Date.MinValue)
// Define an uninitialized date.
let date1 = DateTime()
printf $"{date1}"
if date1.Equals DateTime.MinValue then
printfn $" (Equals Date.MinValue)"
// The example displays the following output:
// 1/1/0001 12:00:00 AM (Equals Date.MinValue)
' Define an uninitialized date.
Dim date1 As Date
Console.Write(date1)
If date1.Equals(Date.MinValue) Then _
Console.WriteLine(" (Equals Date.MinValue)")
' The example displays the following output:
' 1/1/0001 12:00:00 AM (Equals Date.MinValue)
和 MinValueMaxValue 属性可用于确保值在将值传递给 DateTime 构造函数之前位于受支持的范围内。 示例部分中的代码说明了此用法。