Decimal.Increment(Decimal) 操作员

定义

命名空间:

System

程序集:

System.Runtime.dll

Source:

Decimal.cs

将 Decimal 操作数增加 1。

public:
 static System::Decimal operator ++(System::Decimal d) = System::Numerics::IIncrementOperators<System::Decimal>::op_Increment;

public static decimal operator ++ (decimal d);

static member op_Increment : decimal -> decimal

Public Shared op_Increment (d As Decimal) As Decimal

参数

d

Decimal

要递增的值。

返回

Decimal

d 增加 1 后的值。

实现

Increment(TSelf)

例外

OverflowException

返回值小于 Decimal.MinValue 或大于 Decimal.MaxValue。

注解

方法 Increment 定义值增量运算符 Decimal 的操作。 它启用如下代码：

using System;

public class Example
{
   public static void Main()
   {
      Decimal number = 1079.8m;
      Console.WriteLine("Original value:    {0:N}", number);
      Console.WriteLine("Incremented value: {0:N}", ++number);
   }
}
// The example displays the following output:
//       Original value:    1,079.80
//       Incremented value: 1,080.80

open System

let number = 1079.8m
printfn $"Original value:    {number:N}"
printfn $"Incremented value: {Decimal.op_Increment number:N}"

// The example displays the following output:
//       Original value:    1,079.80
//       Incremented value: 1,080.80

某些语言 (（如 Visual Basic) ）缺少增量运算符，可以直接调用 Increment 方法，如以下示例所示。

Module Example
   Public Sub Main()
      Dim number As Decimal = 1079.8d
      Console.WriteLine("Original value:    {0:N}", number)
      Console.WriteLine("Incremented value: {0:N}", Decimal.op_Increment(number))
   End Sub
End Module
' The example displays the following output:
'       Original value:    1,079.80
'       Incremented value: 1,080.80

如果语言不支持自定义运算符，请改为调用 Add 方法，如以下示例所示。

using System;

public class Example
{
   public static void Main()
   {
      Decimal number = 1079.8m;
      Console.WriteLine("Original value:    {0:N}", number);
      Console.WriteLine("Incremented value: {0:N}", Decimal.Add(number, 1));
   }
}
// The example displays the following output:
//       Original value:    1,079.80
//       Incremented value: 1,080.80

open System

let number = 1079.8m
printfn $"Original value:    {number:N}"
printfn $"Incremented value: {Decimal.Add(number, 1):N}"

// The example displays the following output:
//       Original value:    1,079.80
//       Incremented value: 1,080.80

Module Example
   Public Sub Main()
      Dim number As Decimal = 1079.8d
      Console.WriteLine("Original value:    {0:N}", number)
      Console.WriteLine("Incremented value: {0:N}", Decimal.Add(number, 1))
   End Sub
End Module
' The example displays the following output:
'       Original value:    1,079.80
'       Incremented value: 1,080.80

另请参阅

• Add(Decimal, Decimal)