通过

Double.IsNegativeInfinity(Double) 方法

  • 参考

定义

命名空间:
System
程序集:
System.Runtime.dll
程序集:
mscorlib.dll
程序集:
netstandard.dll
Source:
Double.cs
Source:
Double.cs
Source:
Double.cs

返回一个值，通过该值指示指定数字是否计算为负无穷大。

public:
 static bool IsNegativeInfinity(double d);
public:
 static bool IsNegativeInfinity(double d) = System::Numerics::INumberBase<double>::IsNegativeInfinity;
public static bool IsNegativeInfinity (double d);
static member IsNegativeInfinity : double -> bool
Public Shared Function IsNegativeInfinity (d As Double) As Boolean

参数

d
Double

一个双精度浮点数。

返回

Boolean

如果 d 的计算结果为 NegativeInfinity，则为 true；否则为 false。

实现

IsNegativeInfinity(TSelf)

示例

下面的代码示例演示如何使用 IsNegativeInfinity：

// This will return S"true".
Console::WriteLine( "IsNegativeInfinity(-5.0 / 0) == {0}.", Double::IsNegativeInfinity(  -5.0 / zero ) ? (String^)"true" : "false" );

// This will return "true".
Console.WriteLine("IsNegativeInfinity(-5.0 / 0) == {0}.", Double.IsNegativeInfinity(-5.0 / 0) ? "true" : "false");

// This will return "true".
printfn $"IsNegativeInfinity(-5.0 / 0) = {Double.IsNegativeInfinity(-5. / 0.)}."

' This will return "True".
Console.Write("IsNegativeInfinity(-5.0 / 0) = ")
If Double.IsNegativeInfinity(-5 / 0) Then
    Console.WriteLine("True.")
Else
    Console.WriteLine("False.")
End If

if ( d > Double::MaxValue )
{
   Console::WriteLine( "Your number is bigger than a double." );
}

if (d > Double.MaxValue)
   Console.WriteLine("Your number is bigger than a double.");

if d > Double.MaxValue then
   printfn $"Your number is bigger than a double."

If D > Double.MaxValue Then
    Console.WriteLine("Your number is bigger than a double.")
End If

// This will equal Infinity.
Console::WriteLine( "10.0 minus NegativeInfinity equals {0}.", (10.0 - Double::NegativeInfinity) );

// This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals {0}.", (10.0 - Double.NegativeInfinity).ToString());

// This will equal Infinity.
printfn $"10.0 minus NegativeInfinity equals {10.0 - Double.NegativeInfinity}."

' This will equal Infinity.
Console.WriteLine("10.0 minus NegativeInfinity equals " + (10 - Double.NegativeInfinity).ToString() + ".")

注解

浮点运算返回 NegativeInfinity 以指示溢出条件。

适用于

另请参阅