IEquatable<T>.Equals(T) 方法

定义

指示当前对象是否等于同一类型的另一个对象。

public:
 bool Equals(T other);
public bool Equals (T other);
public bool Equals (T? other);
abstract member Equals : 'T -> bool
Public Function Equals (other As T) As Boolean

参数

other
T

一个与此对象进行比较的对象。

返回

如果当前对象等于 other 参数,则为 true;否则为 false

示例

以下示例演示了实现 和 具有两个Person属性LastNameSSN的类IEquatable<T>的部分实现。 如果两个 对象的 属性相同,则Equals方法返回 ;否则返回 FalseTruePersonSSN

using System;
using System.Collections.Generic;
using System.Text.RegularExpressions;

public class Person : IEquatable<Person>
{
   private string uniqueSsn;
   private string lName;

   public Person(string lastName, string ssn)
   {
      if (Regex.IsMatch(ssn, @"\d{9}"))
        uniqueSsn = $"{ssn.Substring(0, 3)}-{ssn.Substring(3, 2)}-{ssn.Substring(5, 4)}";
      else if (Regex.IsMatch(ssn, @"\d{3}-\d{2}-\d{4}"))
         uniqueSsn = ssn;
      else
         throw new FormatException("The social security number has an invalid format.");

      this.LastName = lastName;
   }

   public string SSN
   {
      get { return this.uniqueSsn; }
   }

   public string LastName
   {
      get { return this.lName; }
      set {
         if (String.IsNullOrEmpty(value))
            throw new ArgumentException("The last name cannot be null or empty.");
         else
            this.lName = value;
      }
   }

   public bool Equals(Person other)
   {
      if (other == null)
         return false;

      if (this.uniqueSsn == other.uniqueSsn)
         return true;
      else
         return false;
   }

   public override bool Equals(Object obj)
   {
      if (obj == null)
         return false;

      Person personObj = obj as Person;
      if (personObj == null)
         return false;
      else
         return Equals(personObj);
   }

   public override int GetHashCode()
   {
      return this.SSN.GetHashCode();
   }

   public static bool operator == (Person person1, Person person2)
   {
      if (((object)person1) == null || ((object)person2) == null)
         return Object.Equals(person1, person2);

      return person1.Equals(person2);
   }

   public static bool operator != (Person person1, Person person2)
   {
      if (((object)person1) == null || ((object)person2) == null)
         return ! Object.Equals(person1, person2);

      return ! (person1.Equals(person2));
   }
}
open System
open System.Text.RegularExpressions

type Person(lastName, ssn) =
    let mutable lastName = lastName
    let ssn = 
        if Regex.IsMatch(ssn, @"\d{9}") then
            $"{ssn.Substring(0, 3)}-{ssn.Substring(3, 2)}-{ssn.Substring(5, 4)}"
        elif Regex.IsMatch(ssn, @"\d{3}-\d{2}-\d{4}") then
            ssn
        else
            raise (FormatException "The social security number has an invalid format.")

    member _.SSN =
        ssn

    member _.LastName
        with get () = lastName
        and set (value) =
            if String.IsNullOrEmpty value then
                invalidArg (nameof value) "The last name cannot be null or empty."
            else
                lastName <- value

    static member op_Equality (person1: Person, person2: Person) =
        if box person1 |> isNull || box person2 |> isNull then
            Object.Equals(person1, person2)
        else
            person1.Equals person2

    static member op_Inequality (person1: Person, person2: Person) =
        if box person1 |> isNull || box person2 |> isNull then
            Object.Equals(person1, person2) |> not
        else
            person1.Equals person2 |> not

    override _.GetHashCode() =
        ssn.GetHashCode()

    override this.Equals(obj: obj) =
        match obj with 
        | :? Person as personObj ->
            (this :> IEquatable<_>).Equals personObj
        | _ -> false

    interface IEquatable<Person> with
        member this.Equals(other: Person) =
            match box other with 
            | null -> false
            | _ ->
                this.SSN = other.SSN
Imports System.Collections.Generic
Imports System.Text.RegularExpressions

Public Class Person : Implements IEquatable(Of Person)
   Private uniqueSsn As String
   Private lName As String
   
   Public Sub New(lastName As String, ssn As String)
      If Regex.IsMatch(ssn, "\d{9}") Then
         uniqueSsn = $"{ssn.Substring(0, 3)}-{ssn.Substring(3, 2)}-{ssn.Substring(5, 4)}"
      ElseIf Regex.IsMatch(ssn, "\d{3}-\d{2}-\d{4}") Then
         uniqueSsn = ssn
      Else 
         Throw New FormatException("The social security number has an invalid format.")
      End If
      Me.LastName = lastName
   End Sub
   
   Public ReadOnly Property SSN As String
      Get
         Return Me.uniqueSsn
      End Get      
   End Property
   
   Public Property LastName As String
      Get
         Return Me.lName
      End Get
      Set
         If String.IsNullOrEmpty(value) Then
            Throw New ArgumentException("The last name cannot be null or empty.")
         Else
            lname = value
         End If   
      End Set
   End Property
   
   Public Overloads Function Equals(other As Person) As Boolean _
                   Implements IEquatable(Of Person).Equals
      If other Is Nothing Then Return False
      
      If Me.uniqueSsn = other.uniqueSsn Then
         Return True
      Else
         Return False
      End If
   End Function

   Public Overrides Function Equals(obj As Object) As Boolean
      If obj Is Nothing Then Return False
      
      Dim personObj As Person = TryCast(obj, Person)
      If personObj Is Nothing Then
         Return False
      Else   
         Return Equals(personObj)   
      End If
   End Function   
   
   Public Overrides Function GetHashCode() As Integer
      Return Me.SSN.GetHashCode()
   End Function
   
   Public Shared Operator = (person1 As Person, person2 As Person) As Boolean
      If person1 Is Nothing OrElse person2 Is Nothing Then
         Return Object.Equals(person1, person2)
      End If
         
      Return person1.Equals(person2)
   End Operator
   
   Public Shared Operator <> (person1 As Person, person2 As Person) As Boolean
      If person1 Is Nothing OrElse person2 Is Nothing Then
         Return Not Object.Equals(person1, person2) 
      End If
      
      Return Not person1.Equals(person2)
   End Operator
End Class

Person 然后,对象可以存储在 对象中 List<T> ,并由 方法标识 Contains ,如以下示例所示。

public class TestIEquatable
{
   public static void Main()
   {
      // Create a Person object for each job applicant.
      Person applicant1 = new Person("Jones", "099-29-4999");
      Person applicant2 = new Person("Jones", "199-29-3999");
      Person applicant3 = new Person("Jones", "299-49-6999");

      // Add applicants to a List object.
      List<Person> applicants = new List<Person>();
      applicants.Add(applicant1);
      applicants.Add(applicant2);
      applicants.Add(applicant3);

       // Create a Person object for the final candidate.
       Person candidate = new Person("Jones", "199-29-3999");
       if (applicants.Contains(candidate))
          Console.WriteLine("Found {0} (SSN {1}).",
                             candidate.LastName, candidate.SSN);
      else
         Console.WriteLine("Applicant {0} not found.", candidate.SSN);

      // Call the shared inherited Equals(Object, Object) method.
      // It will in turn call the IEquatable(Of T).Equals implementation.
      Console.WriteLine("{0}({1}) already on file: {2}.",
                        applicant2.LastName,
                        applicant2.SSN,
                        Person.Equals(applicant2, candidate));
   }
}
// The example displays the following output:
//       Found Jones (SSN 199-29-3999).
//       Jones(199-29-3999) already on file: True.
// Create a Person object for each job applicant.
let applicant1 = Person("Jones", "099-29-4999")
let applicant2 = Person("Jones", "199-29-3999")
let applicant3 = Person("Jones", "299-49-6999")

// Add applicants to a List object.
let applicants = ResizeArray()
applicants.Add applicant1
applicants.Add applicant2
applicants.Add applicant3

// Create a Person object for the final candidate.
let candidate = Person("Jones", "199-29-3999")
if applicants.Contains candidate then
    printfn $"Found {candidate.LastName} (SSN {candidate.SSN})."
else
    printfn $"Applicant {candidate.SSN} not found."

// Call the shared inherited Equals(Object, Object) method.
// It will in turn call the IEquatable<T>.Equals implementation.
printfn $"{applicant2.LastName}({applicant2.SSN}) already on file: {Person.Equals(applicant2, candidate)}."

// The example displays the following output:
//       Found Jones (SSN 199-29-3999).
//       Jones(199-29-3999) already on file: True.
Module TestIEquatable
   Public Sub Main()
      ' Create a Person object for each job applicant.
      Dim applicant1 As New Person("Jones", "099-29-4999")
      Dim applicant2 As New Person("Jones", "199-29-3999")
      Dim applicant3 As New Person("Jones", "299-49-6999")

      ' Add applicants to a List object.
      Dim applicants As New List(Of Person)
      applicants.Add(applicant1)
      applicants.Add(applicant2)
      applicants.Add(applicant3)
      
      ' Create a Person object for the final candidate.
      Dim candidate As New Person("Jones", "199-29-3999")
      
      If applicants.Contains(candidate) Then
         Console.WriteLine("Found {0} (SSN {1}).", _
                            candidate.LastName, candidate.SSN)
      Else
         Console.WriteLine("Applicant {0} not found.", candidate.SSN)
      End If         

      ' Call the shared inherited Equals(Object, Object) method.
      ' It will in turn call the IEquatable(Of T).Equals implementation.
      Console.WriteLine("{0}({1}) already on file: {2}.", _ 
                        applicant2.LastName, _
                        applicant2.SSN, _
                        Person.Equals(applicant2, candidate)) 
   End Sub
End Module
' The example displays the following output:
'       Found Jones (SSN 199-29-3999).
'       Jones(199-29-3999) already on file: True.

注解

方法的 Equals 实现旨在执行与当前对象相同类型的 T另一个对象的相等性测试。 在 Equals(T) 以下情况下调用 方法:

换句话说,若要处理类的对象存储在数组或泛型集合对象中的可能性,最好实现 IEquatable<T> 以便可以轻松识别和操作对象。

实现 Equals 方法时,请适当地为泛型类型参数指定的类型定义相等性。 例如,如果类型参数为 ,则 Int32为比较两个 32 位带符号整数时适当定义相等性。

实施者说明

如果实现 Equals(T),还应重写 和 GetHashCode()Equals(Object)基类实现,使其行为与 方法的行为Equals(T)一致。 如果确实重写 Equals(Object),则还会在调用类上的静态 Equals(System.Object, System.Object) 方法时调用重写的实现。 此外,应重载 op_Equalityop_Inequality 运算符。 这可确保所有相等性测试返回一致的结果,如示例所示。

适用于