Dns.GetHostName 方法

定义

命名空间:

System.Net

程序集:

System.Net.NameResolution.dll

Source:

Dns.cs

获取本地计算机的主机名。

public:
 static System::String ^ GetHostName();

public static string GetHostName ();

static member GetHostName : unit -> string

Public Shared Function GetHostName () As String

返回

String

包含本地计算机的 DNS 主机名的字符串。

例外

SocketException

解析本地主机名时遇到错误。

示例

以下示例使用 GetHostName 方法获取本地计算机的主机名。

public:
   void DisplayLocalHostName()
   {
      try
      {
         // Get the local computer host name.
         String^ hostName = Dns::GetHostName();
         Console::WriteLine( "Computer name : {0}", hostName );
      }
      catch ( SocketException^ e ) 
      {
         Console::WriteLine( "SocketException caught!!!" );
         Console::WriteLine( "Source : {0}", e->Source );
         Console::WriteLine( "Message : {0}", e->Message );
      }
      catch ( Exception^ e ) 
      {
         Console::WriteLine( "Exception caught!!!" );
         Console::WriteLine( "Source : {0}", e->Source );
         Console::WriteLine( "Message : {0}", e->Message );
      }
   }

public void DisplayLocalHostName()
{
   try {
      // Get the local computer host name.
      String hostName = Dns.GetHostName();
      Console.WriteLine("Computer name :" + hostName);
   }
   catch(SocketException e) {
      Console.WriteLine("SocketException caught!!!");
      Console.WriteLine("Source : " + e.Source);
      Console.WriteLine("Message : " + e.Message);
   }
   catch(Exception e)
   {
       Console.WriteLine("Exception caught!!!");
       Console.WriteLine("Source : " + e.Source);
       Console.WriteLine("Message : " + e.Message);
   }
}

Public Sub DisplayLocalHostName()
    Try
        ' Get the local computer host name.
        Dim hostName As [String] = Dns.GetHostName()
        Console.WriteLine(("Computer name :" + hostName))
    Catch e As SocketException
        Console.WriteLine("SocketException caught!!!")
        Console.WriteLine(("Source : " + e.Source))
        Console.WriteLine(("Message : " + e.Message))
    Catch e As Exception
        Console.WriteLine("Exception caught!!!")
        Console.WriteLine(("Source : " + e.Source))
        Console.WriteLine(("Message : " + e.Message))
    End Try