Complex.Acos(Complex) 方法

定义

命名空间:

System.Numerics

程序集:

System.Runtime.Numerics.dll

Source:

Complex.cs

返回指定复数的弧余弦值的角度。

public:
 static System::Numerics::Complex Acos(System::Numerics::Complex value);

public static System.Numerics.Complex Acos (System.Numerics.Complex value);

static member Acos : System.Numerics.Complex -> System.Numerics.Complex

Public Shared Function Acos (value As Complex) As Complex

参数

value

Complex

表示余弦的复数。

返回

Complex

角度，以弧度测量，这是 value的弧余弦值。

示例

以下示例演示了 Acos 方法。 它显示，将 Acos 方法返回的值传递给 Cos 方法将返回原始 Complex 值。

using System;
using System.Numerics;

public class Example
{
   public static void Main()
   {
      Complex[] values = { new Complex(.5, 2),
                           new Complex(.5, -2),
                           new Complex(-.5, 2),
                           new Complex(-.3, -.8) };
      foreach (Complex value in values)
         Console.WriteLine("Cos(ACos({0})) = {1}", value,
                           Complex.Cos(Complex.Acos(value)));
   }
}
// The example displays the following output:
//       Cos(ACos((0.5, 2))) = (0.5, 2)
//       Cos(ACos((0.5, -2))) = (0.5, -2)
//       Cos(ACos((-0.5, 2))) = (-0.5, 2)
//       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)

open System.Numerics

let values =
    [ Complex(0.5, 2.); Complex(0.5, -2.); Complex(-0.5, 2.); Complex(-0.3, -0.8) ]

for value in values do
    printfn $"Cos(ACos({value})) = {Complex.Acos value |> Complex.Cos}"
// The example displays the following output:
//       Cos(ACos((0.5, 2))) = (0.5, 2)
//       Cos(ACos((0.5, -2))) = (0.5, -2)
//       Cos(ACos((-0.5, 2))) = (-0.5, 2)
//       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)

Imports System.Numerics

Module Example
   Public Sub Main()
      Dim values() As Complex = { New Complex(.5, 2), 
                                  New Complex(.5, -2),
                                  New Complex(-.5, 2),
                                  New Complex(-.3, -.8) }
      For Each value As Complex In values
         Console.WriteLine("Cos(ACos({0})) = {1}", value, 
                           Complex.Cos(Complex.Acos(value)))
      Next
   End Sub
End Module
' The example displays the following output:
'       Cos(ACos((0.5, 2))) = (0.5, 2)
'       Cos(ACos((0.5, -2))) = (0.5, -2)
'       Cos(ACos((-0.5, 2))) = (-0.5, 2)
'       Cos(ACos((-0.3, -0.8))) = (-0.3, -0.8)

注解

复数 Acos 方法对应于实数的 Math.Acos 方法。

Acos 方法使用以下公式：

(-ImaginaryOne) * Log(value + ImaginaryOne * Sqrt(One - value * value))

另请参阅

• Cos(Complex)
• Acos(Double)