Complex.Asin(Complex) 方法
定义
重要
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返回指定复数的弧正弦值的角度。
public:
static System::Numerics::Complex Asin(System::Numerics::Complex value);
public static System.Numerics.Complex Asin (System.Numerics.Complex value);
static member Asin : System.Numerics.Complex -> System.Numerics.Complex
Public Shared Function Asin (value As Complex) As Complex
参数
- value
- Complex
复数。
返回
角是 value
的弧正弦值。
示例
以下示例演示了 Asin 方法。 它显示,将 Asin 方法返回的值传递给 Sin 方法将返回原始 Complex 值。
using System;
using System.Numerics;
public class Example
{
public static void Main()
{
Complex[] values = { new Complex(2.3, 1.4),
new Complex(-2.3, 1.4),
new Complex(-2.3, -1.4),
new Complex(2.3, -1.4) };
foreach (Complex value in values)
Console.WriteLine("Sin(Asin({0})) = {1}",
value, Complex.Sin(Complex.Asin(value)));
}
}
// The example displays the following output:
// Sin(Asin((2.3, 1.4))) = (2.3, 1.4)
// Sin(Asin((-2.3, 1.4))) = (-2.3, 1.4)
// Sin(Asin((-2.3, -1.4))) = (-2.3, -1.4)
// Sin(Asin((2.3, -1.4))) = (2.3, -1.4)
open System.Numerics
let values =
[ Complex(2.3, 1.4)
Complex(-2.3, 1.4)
Complex(-2.3, -1.4)
Complex(2.3, -1.4) ]
for value in values do
printfn $"Sin(Asin({value})) = {Complex.Asin value |> Complex.Sin}"
// The example displays the following output:
// Sin(Asin((2.3, 1.4))) = (2.3, 1.4)
// Sin(Asin((-2.3, 1.4))) = (-2.3, 1.4)
// Sin(Asin((-2.3, -1.4))) = (-2.3, -1.4)
// Sin(Asin((2.3, -1.4))) = (2.3, -1.4)
Imports System.Numerics
Module Example
Public Sub Main()
Dim values() As Complex = { New Complex(2.3, 1.4),
New Complex(-2.3, 1.4),
New Complex(-2.3, -1.4),
New Complex(2.3, -1.4) }
For Each value As Complex In values
Console.WriteLine("Sin(Asin({0})) = {1}",
value, Complex.Sin(Complex.Asin(value)))
Next
End Sub
End Module
' The example displays the following output:
' Sin(Asin((2.3, 1.4))) = (2.3, 1.4)
' Sin(Asin((-2.3, 1.4))) = (-2.3, 1.4)
' Sin(Asin((-2.3, -1.4))) = (-2.3, -1.4)
' Sin(Asin((2.3, -1.4))) = (2.3, -1.4)
注解
复数 Asin 方法对应于实数的 Math.Asin 方法。
Asin 方法使用以下公式:
-ImaginaryOne * Log(ImaginaryOne * value + Sqrt(One - value * value))