GrammarBuilder.DebugShowPhrases 属性

定义

命名空间:

System.Speech.Recognition

程序集:

System.Speech.dll

包:

System.Speech v9.0.0-preview.3.24172.9

Source:

GrammarBuilder.cs

获取一个字符串，此字符串显示 GrammarBuilder 包含的语法的内容和结构。

public:
 property System::String ^ DebugShowPhrases { System::String ^ get(); };

public string DebugShowPhrases { get; }

member this.DebugShowPhrases : string

Public ReadOnly Property DebugShowPhrases As String

属性值

String

当前内容和结构 GrammarBuilder 的。

示例

以下示例创建一个语音识别语法，用于订购最多四个配料的披萨。 在创建语法之前，它会将 的状态 GrammarBuilder 写入控制台。 此方法生成以下输出：

• GrammarBuilder status: I would like a [cheese,mushroom,tomato,onion,anchovy,chic ken,pepperoni] and [cheese,mushroom,tomato,onion,anchovy,chicken,pepperoni] pizza

private static Grammar CreatePizzaGrammar()
{

  // Create a Choices object with alternatives for toppings.
  Choices toppings = new Choices(new string[] {
    "cheese", "mushroom", "tomato", "onion",
    "anchovy", "chicken", "pepperoni"});

  // Create a GrammarBuilder and append the Choices object.
  GrammarBuilder andToppings = new GrammarBuilder("and", 0, 1);
  andToppings.Append(toppings);

  // Construct the phrase.
  GrammarBuilder gb = new GrammarBuilder("I would like a", 0, 1);
  gb.Append(toppings);
  gb.Append(new GrammarBuilder(andToppings, 0, 3));
  gb.Append("pizza");

  // Write the contents and structure of the GrammarBuilder to the console.
  Console.WriteLine("Grammar content and structure: {0}", gb.DebugShowPhrases);

  // Create the Grammar from the GrammarBuilder.
  Grammar grammar = new Grammar(gb);
  grammar.Name = "Pizza Order";

  return grammar;
}

另请参阅

• 使用 GrammarBuilder 创建语法