WaitHandle.WaitAll 方法
定义
重要
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等待指定数组中的所有元素接收信号。
重载
| 名称 | 说明 |
|---|---|
| WaitAll(WaitHandle[], TimeSpan, Boolean) |
等待指定数组中的所有元素接收信号,使用 TimeSpan 值指定时间间隔,并指定是否在等待之前退出同步域。 |
| WaitAll(WaitHandle[], Int32, Boolean) |
等待指定数组中的所有元素接收信号,使用 Int32 值指定时间间隔并指定是否在等待之前退出同步域。 |
| WaitAll(WaitHandle[], TimeSpan) |
等待指定数组中的所有元素接收信号,并使用 TimeSpan 值指定时间间隔。 |
| WaitAll(WaitHandle[], Int32) |
等待指定数组中的所有元素接收信号,并使用值 Int32 指定时间间隔。 |
| WaitAll(WaitHandle[]) |
等待指定数组中的所有元素接收信号。 |
WaitAll(WaitHandle[], TimeSpan, Boolean)
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
等待指定数组中的所有元素接收信号,使用 TimeSpan 值指定时间间隔,并指定是否在等待之前退出同步域。
public:
static bool WaitAll(cli::array <System::Threading::WaitHandle ^> ^ waitHandles, TimeSpan timeout, bool exitContext);
public static bool WaitAll(System.Threading.WaitHandle[] waitHandles, TimeSpan timeout, bool exitContext);
static member WaitAll : System.Threading.WaitHandle[] * TimeSpan * bool -> bool
Public Shared Function WaitAll (waitHandles As WaitHandle(), timeout As TimeSpan, exitContext As Boolean) As Boolean
参数
- waitHandles
- WaitHandle[]
一个 WaitHandle 数组,其中包含当前实例将等待的对象。 此数组不能包含对同一对象的多个引用。
- exitContext
- Boolean
true 如果处于同步上下文中,请在等待之前退出上下文的同步域(如果在同步的上下文中),然后重新获取它;否则,为 false.
返回
例外
参数 waitHandles 为 null.
-或-
数组中的 waitHandles 一个或多个对象是 null。
-或-
waitHandles 是一个没有元素的数组,.NET Framework 版本为 2.0 或更高版本。
数组 waitHandles 包含重复的元素。
waitHandles 是一个没有元素的数组,.NET Framework 版本为 1.0 或 1.1。
等待已终止,因为线程退出而不释放互斥体。
该 waitHandles 数组包含另一个应用程序域中的 WaitHandle 透明代理。
示例
下面的代码示例演示如何使用线程池来异步创建和写入一组文件。 每个写入操作作为工作项排队,并在完成时发出信号。 主线程等待所有项发出信号,然后退出。
using System;
using System.IO;
using System.Security.Permissions;
using System.Threading;
class Test
{
static void Main()
{
const int numberOfFiles = 5;
string dirName = @"C:\TestTest";
string fileName;
byte[] byteArray;
Random randomGenerator = new Random();
ManualResetEvent[] manualEvents =
new ManualResetEvent[numberOfFiles];
State stateInfo;
if(!Directory.Exists(dirName))
{
Directory.CreateDirectory(dirName);
}
// Queue the work items that create and write to the files.
for(int i = 0; i < numberOfFiles; i++)
{
fileName = string.Concat(
dirName, @"\Test", i.ToString(), ".dat");
// Create random data to write to the file.
byteArray = new byte[1000000];
randomGenerator.NextBytes(byteArray);
manualEvents[i] = new ManualResetEvent(false);
stateInfo =
new State(fileName, byteArray, manualEvents[i]);
ThreadPool.QueueUserWorkItem(new WaitCallback(
Writer.WriteToFile), stateInfo);
}
// Since ThreadPool threads are background threads,
// wait for the work items to signal before exiting.
if(WaitHandle.WaitAll(
manualEvents, new TimeSpan(0, 0, 5), false))
{
Console.WriteLine("Files written - main exiting.");
}
else
{
// The wait operation times out.
Console.WriteLine("Error writing files - main exiting.");
}
}
}
// Maintain state to pass to WriteToFile.
class State
{
public string fileName;
public byte[] byteArray;
public ManualResetEvent manualEvent;
public State(string fileName, byte[] byteArray,
ManualResetEvent manualEvent)
{
this.fileName = fileName;
this.byteArray = byteArray;
this.manualEvent = manualEvent;
}
}
class Writer
{
static int workItemCount = 0;
Writer() {}
public static void WriteToFile(object state)
{
int workItemNumber = workItemCount;
Interlocked.Increment(ref workItemCount);
Console.WriteLine("Starting work item {0}.",
workItemNumber.ToString());
State stateInfo = (State)state;
FileStream fileWriter = null;
// Create and write to the file.
try
{
fileWriter = new FileStream(
stateInfo.fileName, FileMode.Create);
fileWriter.Write(stateInfo.byteArray,
0, stateInfo.byteArray.Length);
}
finally
{
if(fileWriter != null)
{
fileWriter.Close();
}
// Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.",
workItemNumber.ToString());
stateInfo.manualEvent.Set();
}
}
}
Imports System.IO
Imports System.Security.Permissions
Imports System.Threading
Public Class Test
' WaitHandle.WaitAll requires a multithreaded apartment
' when using multiple wait handles.
<MTAThreadAttribute> _
Shared Sub Main()
Const numberOfFiles As Integer = 5
Dim dirName As String = "C:\TestTest"
Dim fileName As String
Dim byteArray() As Byte
Dim randomGenerator As New Random()
Dim manualEvents(numberOfFiles - 1) As ManualResetEvent
Dim stateInfo As State
If Directory.Exists(dirName) <> True Then
Directory.CreateDirectory(dirName)
End If
' Queue the work items that create and write to the files.
For i As Integer = 0 To numberOfFiles - 1
fileName = String.Concat( _
dirName, "\Test", i.ToString(), ".dat")
' Create random data to write to the file.
byteArray = New Byte(1000000){}
randomGenerator.NextBytes(byteArray)
manualEvents(i) = New ManualResetEvent(false)
stateInfo = _
New State(fileName, byteArray, manualEvents(i))
ThreadPool.QueueUserWorkItem(AddressOf _
Writer.WriteToFile, stateInfo)
Next i
' Since ThreadPool threads are background threads,
' wait for the work items to signal before exiting.
If WaitHandle.WaitAll( _
manualEvents, New TimeSpan(0, 0, 5), false) = True Then
Console.WriteLine("Files written - main exiting.")
Else
' The wait operation times out.
Console.WriteLine("Error writing files - main exiting.")
End If
End Sub
End Class
' Maintain state to pass to WriteToFile.
Public Class State
Public fileName As String
Public byteArray As Byte()
Public manualEvent As ManualResetEvent
Sub New(fileName As String, byteArray() As Byte, _
manualEvent As ManualResetEvent)
Me.fileName = fileName
Me.byteArray = byteArray
Me.manualEvent = manualEvent
End Sub
End Class
Public Class Writer
Private Sub New()
End Sub
Shared workItemCount As Integer = 0
Shared Sub WriteToFile(state As Object)
Dim workItemNumber As Integer = workItemCount
Interlocked.Increment(workItemCount)
Console.WriteLine("Starting work item {0}.", _
workItemNumber.ToString())
Dim stateInfo As State = CType(state, State)
Dim fileWriter As FileStream = Nothing
' Create and write to the file.
Try
fileWriter = New FileStream( _
stateInfo.fileName, FileMode.Create)
fileWriter.Write(stateInfo.byteArray, _
0, stateInfo.byteArray.Length)
Finally
If Not fileWriter Is Nothing Then
fileWriter.Close()
End If
' Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.", _
workItemNumber.ToString())
stateInfo.manualEvent.Set()
End Try
End Sub
End Class
注解
如果 timeout 为零,则该方法不会阻止。 它测试等待句柄的状态并立即返回。
如果放弃互斥体,则会引发一个 AbandonedMutexException 。 放弃的互斥体通常表示存在严重的编码错误。 对于系统范围的互斥体,它可能表示应用程序已突然终止(例如,使用 Windows 任务管理器)。 异常包含可用于调试的信息。
此方法 WaitAll 在等待终止时返回,这意味着所有句柄都发出信号或超时。 如果传递了 64 个以上的句柄,则会引发 a NotSupportedException 。 如果数组包含重复项,调用将失败。
的最大值 timeout 为 Int32.MaxValue.
退出上下文
除非从非默认托管上下文内部调用此方法,否则参数 exitContext 不起作用。 如果线程在对派生自 ContextBoundObject的类实例的调用中,则托管上下文可以是非默认上下文。 即使当前在未派生自 ContextBoundObject的类上执行方法,例如 String,如果在 ContextBoundObject 当前应用程序域中的堆栈上,也可以位于非默认上下文中。
当代码在非默认上下文中执行时,指定 true 它 exitContext 会导致线程在执行此方法之前退出非默认托管上下文(即转换到默认上下文)。 调用此方法后,线程将返回到原始非默认上下文。
当上下文绑定类具有 SynchronizationAttribute 属性时,退出上下文可能很有用。 在这种情况下,对类成员的所有调用都会自动同步,并且同步域是该类的整个代码正文。 如果成员调用堆栈中的代码调用此方法并指定 true , exitContext则线程将退出同步域,从而允许在调用对象的任何成员时阻止的线程继续。 此方法返回时,发出调用的线程必须等待重新输入同步域。
适用于
WaitAll(WaitHandle[], Int32, Boolean)
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
等待指定数组中的所有元素接收信号,使用 Int32 值指定时间间隔并指定是否在等待之前退出同步域。
public:
static bool WaitAll(cli::array <System::Threading::WaitHandle ^> ^ waitHandles, int millisecondsTimeout, bool exitContext);
public static bool WaitAll(System.Threading.WaitHandle[] waitHandles, int millisecondsTimeout, bool exitContext);
static member WaitAll : System.Threading.WaitHandle[] * int * bool -> bool
Public Shared Function WaitAll (waitHandles As WaitHandle(), millisecondsTimeout As Integer, exitContext As Boolean) As Boolean
参数
- waitHandles
- WaitHandle[]
一个 WaitHandle 数组,其中包含当前实例将等待的对象。 此数组不能包含对同一对象(重复项)的多个引用。
- exitContext
- Boolean
true 如果处于同步上下文中,请在等待之前退出上下文的同步域(如果在同步的上下文中),然后重新获取它;否则,为 false.
返回
例外
参数 waitHandles 为 null.
-或-
数组中的 waitHandles 一个或多个对象是 null。
-或-
waitHandles 是一个没有元素的数组,.NET Framework 版本为 2.0 或更高版本。
数组 waitHandles 包含重复的元素。
waitHandles 是一个没有元素的数组,.NET Framework 版本为 1.0 或 1.1。
millisecondsTimeout 是非 -1 的负数,表示无限超时。
等待已完成,因为线程退出而不释放互斥体。
该 waitHandles 数组包含另一个应用程序域中的 WaitHandle 透明代理。
示例
下面的代码示例演示如何使用线程池来异步创建和写入一组文件。 每个写入操作作为工作项排队,并在完成时发出信号。 主线程等待所有项发出信号,然后退出。
using System;
using System.IO;
using System.Security.Permissions;
using System.Threading;
class Test
{
static void Main()
{
const int numberOfFiles = 5;
string dirName = @"C:\TestTest";
string fileName;
byte[] byteArray;
Random randomGenerator = new Random();
ManualResetEvent[] manualEvents =
new ManualResetEvent[numberOfFiles];
State stateInfo;
if(!Directory.Exists(dirName))
{
Directory.CreateDirectory(dirName);
}
// Queue the work items that create and write to the files.
for(int i = 0; i < numberOfFiles; i++)
{
fileName = string.Concat(
dirName, @"\Test", i.ToString(), ".dat");
// Create random data to write to the file.
byteArray = new byte[1000000];
randomGenerator.NextBytes(byteArray);
manualEvents[i] = new ManualResetEvent(false);
stateInfo =
new State(fileName, byteArray, manualEvents[i]);
ThreadPool.QueueUserWorkItem(new WaitCallback(
Writer.WriteToFile), stateInfo);
}
// Since ThreadPool threads are background threads,
// wait for the work items to signal before exiting.
if(WaitHandle.WaitAll(manualEvents, 5000, false))
{
Console.WriteLine("Files written - main exiting.");
}
else
{
// The wait operation times out.
Console.WriteLine("Error writing files - main exiting.");
}
}
}
// Maintain state to pass to WriteToFile.
class State
{
public string fileName;
public byte[] byteArray;
public ManualResetEvent manualEvent;
public State(string fileName, byte[] byteArray,
ManualResetEvent manualEvent)
{
this.fileName = fileName;
this.byteArray = byteArray;
this.manualEvent = manualEvent;
}
}
class Writer
{
static int workItemCount = 0;
Writer() {}
public static void WriteToFile(object state)
{
int workItemNumber = workItemCount;
Interlocked.Increment(ref workItemCount);
Console.WriteLine("Starting work item {0}.",
workItemNumber.ToString());
State stateInfo = (State)state;
FileStream fileWriter = null;
// Create and write to the file.
try
{
fileWriter = new FileStream(
stateInfo.fileName, FileMode.Create);
fileWriter.Write(stateInfo.byteArray,
0, stateInfo.byteArray.Length);
}
finally
{
if(fileWriter != null)
{
fileWriter.Close();
}
// Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.",
workItemNumber.ToString());
stateInfo.manualEvent.Set();
}
}
}
Imports System.IO
Imports System.Security.Permissions
Imports System.Threading
Public Class Test
' WaitHandle.WaitAll requires a multithreaded apartment
' when using multiple wait handles.
<MTAThreadAttribute> _
Shared Sub Main()
Const numberOfFiles As Integer = 5
Dim dirName As String = "C:\TestTest"
Dim fileName As String
Dim byteArray() As Byte
Dim randomGenerator As New Random()
Dim manualEvents(numberOfFiles - 1) As ManualResetEvent
Dim stateInfo As State
If Directory.Exists(dirName) <> True Then
Directory.CreateDirectory(dirName)
End If
' Queue the work items that create and write to the files.
For i As Integer = 0 To numberOfFiles - 1
fileName = String.Concat( _
dirName, "\Test", i.ToString(), ".dat")
' Create random data to write to the file.
byteArray = New Byte(1000000){}
randomGenerator.NextBytes(byteArray)
manualEvents(i) = New ManualResetEvent(false)
stateInfo = _
New State(fileName, byteArray, manualEvents(i))
ThreadPool.QueueUserWorkItem(AddressOf _
Writer.WriteToFile, stateInfo)
Next i
' Since ThreadPool threads are background threads,
' wait for the work items to signal before exiting.
If WaitHandle.WaitAll(manualEvents, 5000, false) = True Then
Console.WriteLine("Files written - main exiting.")
Else
' The wait operation times out.
Console.WriteLine("Error writing files - main exiting.")
End If
End Sub
End Class
' Maintain state to pass to WriteToFile.
Public Class State
Public fileName As String
Public byteArray As Byte()
Public manualEvent As ManualResetEvent
Sub New(fileName As String, byteArray() As Byte, _
manualEvent As ManualResetEvent)
Me.fileName = fileName
Me.byteArray = byteArray
Me.manualEvent = manualEvent
End Sub
End Class
Public Class Writer
Private Sub New()
End Sub
Shared workItemCount As Integer = 0
Shared Sub WriteToFile(state As Object)
Dim workItemNumber As Integer = workItemCount
Interlocked.Increment(workItemCount)
Console.WriteLine("Starting work item {0}.", _
workItemNumber.ToString())
Dim stateInfo As State = CType(state, State)
Dim fileWriter As FileStream = Nothing
' Create and write to the file.
Try
fileWriter = New FileStream( _
stateInfo.fileName, FileMode.Create)
fileWriter.Write(stateInfo.byteArray, _
0, stateInfo.byteArray.Length)
Finally
If Not fileWriter Is Nothing Then
fileWriter.Close()
End If
' Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.", _
workItemNumber.ToString())
stateInfo.manualEvent.Set()
End Try
End Sub
End Class
注解
如果 millisecondsTimeout 为零,则该方法不会阻止。 它测试等待句柄的状态并立即返回。
如果放弃互斥体,则会引发一个 AbandonedMutexException 。 放弃的互斥体通常表示存在严重的编码错误。 对于系统范围的互斥体,它可能表示应用程序已突然终止(例如,使用 Windows 任务管理器)。 异常包含可用于调试的信息。
此方法 WaitAll 在等待终止时返回,这意味着在发出所有句柄或超时时发出信号。 如果传递了 64 个以上的句柄,则会引发 a NotSupportedException 。 如果数组中存在重复项,调用将失败并出现一个 DuplicateWaitObjectException。
退出上下文
除非从非默认托管上下文内部调用此方法,否则参数 exitContext 不起作用。 如果线程在对派生自 ContextBoundObject的类实例的调用中,则托管上下文可以是非默认上下文。 即使当前在未派生自 ContextBoundObject的类上执行方法,例如 String,如果在 ContextBoundObject 当前应用程序域中的堆栈上,也可以位于非默认上下文中。
当代码在非默认上下文中执行时,指定 true 它 exitContext 会导致线程在执行此方法之前退出非默认托管上下文(即转换到默认上下文)。 调用此方法后,线程将返回到原始非默认上下文。
当上下文绑定类具有 SynchronizationAttribute 属性时,退出上下文可能很有用。 在这种情况下,对类成员的所有调用都会自动同步,并且同步域是该类的整个代码正文。 如果成员调用堆栈中的代码调用此方法并指定 true , exitContext则线程将退出同步域,从而允许在调用对象的任何成员时阻止的线程继续。 此方法返回时,发出调用的线程必须等待重新输入同步域。
适用于
WaitAll(WaitHandle[], TimeSpan)
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
等待指定数组中的所有元素接收信号,并使用 TimeSpan 值指定时间间隔。
public:
static bool WaitAll(cli::array <System::Threading::WaitHandle ^> ^ waitHandles, TimeSpan timeout);
public static bool WaitAll(System.Threading.WaitHandle[] waitHandles, TimeSpan timeout);
static member WaitAll : System.Threading.WaitHandle[] * TimeSpan -> bool
Public Shared Function WaitAll (waitHandles As WaitHandle(), timeout As TimeSpan) As Boolean
参数
- waitHandles
- WaitHandle[]
一个 WaitHandle 数组,其中包含当前实例将等待的对象。 此数组不能包含对同一对象的多个引用。
返回
例外
参数 waitHandles 为 null.
-或-
数组中的 waitHandles 一个或多个对象是 null。
-或-
waitHandles 是一个没有元素的数组。
数组 waitHandles 包含重复的元素。
等待已终止,因为线程退出而不释放互斥体。
该 waitHandles 数组包含另一个应用程序域中的 WaitHandle 透明代理。
注解
如果 timeout 为零,则该方法不会阻止。 它测试等待句柄的状态并立即返回。
此方法 WaitAll 在等待终止时返回,这意味着所有句柄都发出信号或超时。 如果传递了 64 个以上的句柄,则会引发 a NotSupportedException 。 如果数组包含重复项,调用将失败。
的最大值 timeout 为 Int32.MaxValue.
调用此方法重载与调用WaitAll(WaitHandle[], TimeSpan, Boolean)重载和指定falseexitContext重载相同。
适用于
WaitAll(WaitHandle[], Int32)
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
等待指定数组中的所有元素接收信号,并使用值 Int32 指定时间间隔。
public:
static bool WaitAll(cli::array <System::Threading::WaitHandle ^> ^ waitHandles, int millisecondsTimeout);
public static bool WaitAll(System.Threading.WaitHandle[] waitHandles, int millisecondsTimeout);
static member WaitAll : System.Threading.WaitHandle[] * int -> bool
Public Shared Function WaitAll (waitHandles As WaitHandle(), millisecondsTimeout As Integer) As Boolean
参数
- waitHandles
- WaitHandle[]
一个 WaitHandle 数组,其中包含当前实例将等待的对象。 此数组不能包含对同一对象(重复项)的多个引用。
返回
例外
参数 waitHandles 为 null.
-或-
数组中的 waitHandles 一个或多个对象是 null。
-或-
waitHandles 是一个没有元素的数组。
数组 waitHandles 包含重复的元素。
millisecondsTimeout 是非 -1 的负数,表示无限超时。
等待已完成,因为线程退出而不释放互斥体。
该 waitHandles 数组包含另一个应用程序域中的 WaitHandle 透明代理。
注解
如果 millisecondsTimeout 为零,则该方法不会阻止。 它测试等待句柄的状态并立即返回。
此方法 WaitAll 在等待终止时返回,这意味着在发出所有句柄或超时时发出信号。 如果传递了 64 个以上的句柄,则会引发 a NotSupportedException 。 如果数组中存在重复项,调用将失败并出现一个 DuplicateWaitObjectException。
调用此方法重载与调用WaitAll(WaitHandle[], Int32, Boolean)重载和指定falseexitContext重载相同。
适用于
WaitAll(WaitHandle[])
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
- Source:
- WaitHandle.cs
等待指定数组中的所有元素接收信号。
public:
static bool WaitAll(cli::array <System::Threading::WaitHandle ^> ^ waitHandles);
public static bool WaitAll(System.Threading.WaitHandle[] waitHandles);
static member WaitAll : System.Threading.WaitHandle[] -> bool
Public Shared Function WaitAll (waitHandles As WaitHandle()) As Boolean
参数
- waitHandles
- WaitHandle[]
一个 WaitHandle 数组,其中包含当前实例将等待的对象。 此数组不能包含对同一对象的多个引用。
返回
true 当每个元素 waitHandles 都收到信号时,否则该方法永远不会返回。
例外
参数 waitHandles 为 null. -或-
数组中的 waitHandles 一个或多个对象为 null。
-或-
waitHandles 是一个没有元素的数组,.NET Framework 版本为 2.0 或更高版本。
数组 waitHandles 包含重复的元素。
waitHandles 是一个没有元素的数组,.NET Framework 版本为 1.0 或 1.1。
等待已终止,因为线程退出而不释放互斥体。
该 waitHandles 数组包含另一个应用程序域中的 WaitHandle 透明代理。
示例
下面的代码示例演示如何使用线程池来异步创建和写入一组文件。 每个写入操作作为工作项排队,并在完成时发出信号。 主线程等待所有项发出信号,然后退出。
using System;
using System.IO;
using System.Security.Permissions;
using System.Threading;
class Test
{
static void Main()
{
const int numberOfFiles = 5;
string dirName = @"C:\TestTest";
string fileName;
byte[] byteArray;
Random randomGenerator = new Random();
ManualResetEvent[] manualEvents =
new ManualResetEvent[numberOfFiles];
State stateInfo;
if(!Directory.Exists(dirName))
{
Directory.CreateDirectory(dirName);
}
// Queue the work items that create and write to the files.
for(int i = 0; i < numberOfFiles; i++)
{
fileName = string.Concat(
dirName, @"\Test", i.ToString(), ".dat");
// Create random data to write to the file.
byteArray = new byte[1000000];
randomGenerator.NextBytes(byteArray);
manualEvents[i] = new ManualResetEvent(false);
stateInfo =
new State(fileName, byteArray, manualEvents[i]);
ThreadPool.QueueUserWorkItem(new WaitCallback(
Writer.WriteToFile), stateInfo);
}
// Since ThreadPool threads are background threads,
// wait for the work items to signal before exiting.
WaitHandle.WaitAll(manualEvents);
Console.WriteLine("Files written - main exiting.");
}
}
// Maintain state to pass to WriteToFile.
class State
{
public string fileName;
public byte[] byteArray;
public ManualResetEvent manualEvent;
public State(string fileName, byte[] byteArray,
ManualResetEvent manualEvent)
{
this.fileName = fileName;
this.byteArray = byteArray;
this.manualEvent = manualEvent;
}
}
class Writer
{
static int workItemCount = 0;
Writer() {}
public static void WriteToFile(object state)
{
int workItemNumber = workItemCount;
Interlocked.Increment(ref workItemCount);
Console.WriteLine("Starting work item {0}.",
workItemNumber.ToString());
State stateInfo = (State)state;
FileStream fileWriter = null;
// Create and write to the file.
try
{
fileWriter = new FileStream(
stateInfo.fileName, FileMode.Create);
fileWriter.Write(stateInfo.byteArray,
0, stateInfo.byteArray.Length);
}
finally
{
if(fileWriter != null)
{
fileWriter.Close();
}
// Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.",
workItemNumber.ToString());
stateInfo.manualEvent.Set();
}
}
}
Imports System.IO
Imports System.Security.Permissions
Imports System.Threading
Public Class Test
' WaitHandle.WaitAll requires a multithreaded apartment
' when using multiple wait handles.
<MTAThreadAttribute> _
Shared Sub Main()
Const numberOfFiles As Integer = 5
Dim dirName As String = "C:\TestTest"
Dim fileName As String
Dim byteArray() As Byte
Dim randomGenerator As New Random()
Dim manualEvents(numberOfFiles - 1) As ManualResetEvent
Dim stateInfo As State
If Directory.Exists(dirName) <> True Then
Directory.CreateDirectory(dirName)
End If
' Queue the work items that create and write to the files.
For i As Integer = 0 To numberOfFiles - 1
fileName = String.Concat( _
dirName, "\Test", i.ToString(), ".dat")
' Create random data to write to the file.
byteArray = New Byte(1000000){}
randomGenerator.NextBytes(byteArray)
manualEvents(i) = New ManualResetEvent(false)
stateInfo = _
New State(fileName, byteArray, manualEvents(i))
ThreadPool.QueueUserWorkItem(AddressOf _
Writer.WriteToFile, stateInfo)
Next i
' Since ThreadPool threads are background threads,
' wait for the work items to signal before exiting.
WaitHandle.WaitAll(manualEvents)
Console.WriteLine("Files written - main exiting.")
End Sub
End Class
' Maintain state to pass to WriteToFile.
Public Class State
Public fileName As String
Public byteArray As Byte()
Public manualEvent As ManualResetEvent
Sub New(fileName As String, byteArray() As Byte, _
manualEvent As ManualResetEvent)
Me.fileName = fileName
Me.byteArray = byteArray
Me.manualEvent = manualEvent
End Sub
End Class
Public Class Writer
Private Sub New()
End Sub
Shared workItemCount As Integer = 0
Shared Sub WriteToFile(state As Object)
Dim workItemNumber As Integer = workItemCount
Interlocked.Increment(workItemCount)
Console.WriteLine("Starting work item {0}.", _
workItemNumber.ToString())
Dim stateInfo As State = CType(state, State)
Dim fileWriter As FileStream = Nothing
' Create and write to the file.
Try
fileWriter = New FileStream( _
stateInfo.fileName, FileMode.Create)
fileWriter.Write(stateInfo.byteArray, _
0, stateInfo.byteArray.Length)
Finally
If Not fileWriter Is Nothing Then
fileWriter.Close()
End If
' Signal Main that the work item has finished.
Console.WriteLine("Ending work item {0}.", _
workItemNumber.ToString())
stateInfo.manualEvent.Set()
End Try
End Sub
End Class
注解
AbandonedMutexException 是 .NET Framework 版本 2.0 中的新增功能。 在以前的版本中,此方法 WaitAll 在 true 放弃互斥体时返回。 放弃的互斥体通常表示存在严重的编码错误。 对于系统范围的互斥体,它可能表示应用程序已突然终止(例如,使用 Windows 任务管理器)。 异常包含可用于调试的信息。
当发出所有句柄的信号时,该方法 WaitAll 将返回。 如果传递了 64 个以上的句柄,则会引发 a NotSupportedException 。 如果数组包含重复项,则调用失败并显示一个 DuplicateWaitObjectException。
调用此方法重载等效于调用WaitAll(WaitHandle[], Int32, Boolean)方法重载并为其指定 -1 (或Timeout.Infinite) millisecondsTimeouttrue 。exitContext